Parse error: syntax error, unexpected '<' in F:\xampp\htdocs\taranaki2.php on line 82

dean012 · November 30, 2013

Parse error: syntax error, unexpected '<' in F:\xampp\htdocs\taranaki2.php on line 82

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<!--


-->
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta name="keywords" content="" />
<meta name="description" content="" />
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title>Yakity Yak</title>
<link href='http://fonts.googleapis.com/css?family=Oswald:400,300' rel='stylesheet' type='text/css'>
<link href='http://fonts.googleapis.com/css?family=Abel|Satisfy' rel='stylesheet' type='text/css'>
<link href="style.css" rel="stylesheet" type="text/css" media="screen" />
</head>
<body>
<div id="wrapper">
  <p><!-- end #header --></p>
  <div id="header" class="container">
    <div id="logo">
      <h1><a href="#">Yakity Yak</a></h1>
    </div>
    <div id="menu">
      <ul>
        <li class="current_page_item"><a href="file:///D:/blackpolish/homepage.php">Homepage</a></li>
        <li><a href="file:///D:/blackpolish/trip.php">Destinations</a></li>
        <li><a href="#">contact </a></li>
        <li><a href="#">Login</a></li>
		<li><a href="adminlogin.php">Leader</a></li>
        <li></li>
        <li></li>
      </ul>
    </div>
  </div>
  <blockquote>
    <blockquote>
      <p> <center><img src="../../Documents/Unnamed Site 2/IMG_1913.jpg" width="999" height="388"  alt=""/></center>  </p>
    </blockquote>
  </blockquote>
  <div id="page">
    <div class="post">
      <h2 class="title"><a href="#">Taranaki</a></h2>
			<div class="entry">
				<table border='1'>
    
    </div>

	


 
</body>
</html>
<?php
/* This code establishes a connection with the database on the server. 
The mysql_connect accepts three parameters. The mysql_select_db attempts to select the database that data will be retrived from. 
It accepts two parameters, one is the name of the database and the other is the connection variable.*/
   
$con=mysqli_connect("localhost","root","","assesment");
// Check connection
if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }
if(isset($_POST['update'])){
$UpdateQuery= "UPDATE assesment SET ID='$_POST[ID]',Destination='$_POST[Destination]',Difficulty='$_POST[Difficulty]' Where ID=[hidden]";
mysql_query($UpdateQuery, $con);
};

$result = mysqli_query($con,"SELECT * FROM taranaki");

echo "<table border='1'>
<tr>
<th>ID</th>
<th>Destination</th>
<th>Difficulty</th>
</tr>";

while($row = mysqli_fetch_array($result))
  echo "<form action=trip2.php method=post>";{
  echo "<tr>";
  echo "<td>" . <input type="text"  name="ID" value=""/>.         $row['ID'] . "</td>";
  echo "<td>" . <input type="text" name="Destination" value=""/>. $row['Destination'] . "</td>";
  echo "<td>" . <input type="text"  name="Difficulty" value=""/>. $row['Difficulty'] . "</td>";
  echo "<td>" . <input type="hidden"  name="hidden" value=""/>.   $row['ID'] . " </td>";
  echo "<td>". <input type="text" name="update" value="update"/>. "</td>";
  echo "</tr>";
  echo "</form>";}
echo "</table>";

mysqli_close($con);
?>

dean012 · November 30, 2013

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Parse error: syntax error, unexpected '<' in F:\xampp\htdocs\taranaki2.php on line 82

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