Unable to login (PHP & mySQL

carophp · January 9, 2014

When I try to login with my username and password, nothing happens. I only get an error from this line in login.php:

"if ($_POST['action']=='logout') {"

So what could be wrong?

Login.php:

<?php
session_start();
/*Om användaren har tryck på loggut-knappen så verkställs sessionen.*/


if ($_POST['action']=='logout') {
  session_unset();
}


if (! isset($_SESSION['username'])) {


 if (isset($_POST['username'])) {
$username = addslashes($_POST['username']); 


$pswd = addslashes($_POST['pswd']);


/*Här försöker vi koppla upp mot databasen*/
mysql_connect('localhost', 'root', '')
 or die("Kan inte koppla upp mot db-servern");
mysql_select_db("db_film")
 or die("Kan inte koppla upp mot db");


/*Här hämtas namn, användarnamn och lösenord från tabellen users i databasen.  Om de inskrivna värdena stämmer överens med uppgifterna i          databasen så skickas vi till publishpost.php. */
$query = "SELECT username FROM users WHERE username='$username' AND pswd=md5('$pswd')";
echo "<pre>$query</pre>";
$result = mysql_query($query);
if (mysql_num_rows($result) == 1){
// $_SESSION['firstname'] = mysql_result($result,0,"firstname");
 $_SESSION['username'] = mysql_result($result,0,"username");
 $user = $_POST['username'];
 $salt = "somestring";
 $_SESSION['token'] = md5($salt . $user . $salt);
 $token = $_SESSION['token'];
 header("location: publishpost.php");


}
/*Om uppgifterna inte stämmer så stannar användaren kvar på login.php och en text skrivs ut som talar om att man inte har blivit                  inloggad.*/
else 
{
$username = $_SESSION['username'];
header("location: login.php");
echo ("Du är inte inloggad");
} 
 }
} 
?>

Checklogin.php:

<?php
/*
En session för att logga in
*/
session_start();

$user = $_SESSION['username'];
$salt = "somestring";
$token = md5($salt . $user . $salt);


if (isset($_SESSION['name']) AND $_SESSION['token'] == $token) 
{
 $name = $_SESSION['name'];
}


else 
{
header("location: login.php");
}
?>

adam_bray · January 9, 2014

What error do you get?

If you use this, what happens? -

$result = mysql_query($query) or die( mysql_error() );

carophp · January 9, 2014

What error do you get?

If you use this, what happens? -
$result = mysql_query($query) or die( mysql_error() );

I get this message:

SELECT username FROM users WHERE username='Ennon' AND pswd=md5('aslan')

Ch0cu3r · January 9, 2014

I get this message:

SELECT username FROM users WHERE username='Ennon' AND pswd=md5('aslan')

That is because you are echo'ing the query before hand

echo "<pre>$query</pre>";

Remove or comment the line above. This will cause the header redirect from working.

carophp · January 9, 2014

That is because you are echo'ing the query before hand
echo "<pre>$query</pre>";
Remove or comment the line above. This will cause the header redirect from working.

I commented the line but still unable to log in!

Ch0cu3r · January 9, 2014

Use this as login.php. Post what messages are displayed.

<?php
ini_set('display_errors', 1);
error_reporting(E_ALL);

session_start();
/*Om användaren har tryck på loggut-knappen så verkställs sessionen.*/


if (isset($_POST['action']) && $_POST['action']=='logout') {
  session_unset();
}

echo "Attempting to login....<br>"

if (! isset($_SESSION['username']))
{
    if (isset($_POST['username']))
    {
        $username = addslashes($_POST['username']); 
        $pswd = addslashes($_POST['pswd']);

        echo "Username $username<br>Password $pswd<br>";

        /*Här försöker vi koppla upp mot databasen*/
        mysql_connect('localhost', 'root', '')
         or die("Kan inte koppla upp mot db-servern");
        mysql_select_db("db_film")
         or die("Kan inte koppla upp mot db");


        /*Här hämtas namn, användarnamn och lösenord från tabellen users i databasen.  Om de inskrivna värdena stämmer överens med uppgifterna i          databasen så skickas vi till publishpost.php. */
        $query = "SELECT username FROM users WHERE username='$username' AND pswd=md5('$pswd')";
        echo "Query to run...<pre>$query</pre>";
        $result = mysql_query($query);
        if (mysql_num_rows($result) == 1)
        {
            echo 'Success logged in! Credentials matched<br>';
            // $_SESSION['firstname'] = mysql_result($result,0,"firstname");
            $_SESSION['username'] = mysql_result($result,0,"username");
            $user = $_POST['username'];
            $salt = "somestring";
            $_SESSION['token'] = md5($salt . $user . $salt);
            $token = $_SESSION['token'];

            printf('<pre>$_SESSION data = %s</pre>', print_r($_SESSION, true));
            
            //header("location: publishpost.php");
        }
        /*Om uppgifterna inte stämmer så stannar användaren kvar på login.php och en text skrivs ut som talar om att man inte har blivit                  inloggad.*/
        else 
        {
            echo "Login failed! Username/password wrong<br>";

            $username = $_SESSION['username'];
            //header("location: login.php");
            echo ("Du är inte inloggad");
        }
    }
    else
    {
        echo "\$_POST['username'] does not exist<br>Can not loggin";
    }
}
else
{
    echo "\$_SESSION['username'] exists. Already logged in?<br>";
}
?>

carophp · January 9, 2014

Use this as login.php. Post what messages are displayed.

<?php
ini_set('display_errors', 1);
error_reporting(E_ALL);

session_start();
/*Om användaren har tryck på loggut-knappen så verkställs sessionen.*/


if (isset($_POST['action']) && $_POST['action']=='logout') {
  session_unset();
}

echo "Attempting to login....<br>"

if (! isset($_SESSION['username']))
{
    if (isset($_POST['username']))
    {
        $username = addslashes($_POST['username']); 
        $pswd = addslashes($_POST['pswd']);

        echo "Username $username<br>Password $pswd<br>";

        /*Här försöker vi koppla upp mot databasen*/
        mysql_connect('localhost', 'root', '')
         or die("Kan inte koppla upp mot db-servern");
        mysql_select_db("db_film")
         or die("Kan inte koppla upp mot db");


        /*Här hämtas namn, användarnamn och lösenord från tabellen users i databasen.  Om de inskrivna värdena stämmer överens med uppgifterna i          databasen så skickas vi till publishpost.php. */
        $query = "SELECT username FROM users WHERE username='$username' AND pswd=md5('$pswd')";
        echo "Query to run...<pre>$query</pre>";
        $result = mysql_query($query);
        if (mysql_num_rows($result) == 1)
        {
            echo 'Success logged in! Credentials matched<br>';
            // $_SESSION['firstname'] = mysql_result($result,0,"firstname");
            $_SESSION['username'] = mysql_result($result,0,"username");
            $user = $_POST['username'];
            $salt = "somestring";
            $_SESSION['token'] = md5($salt . $user . $salt);
            $token = $_SESSION['token'];

            printf('<pre>$_SESSION data = %s</pre>', print_r($_SESSION, true));
            
            //header("location: publishpost.php");
        }
        /*Om uppgifterna inte stämmer så stannar användaren kvar på login.php och en text skrivs ut som talar om att man inte har blivit                  inloggad.*/
        else 
        {
            echo "Login failed! Username/password wrong<br>";

            $username = $_SESSION['username'];
            //header("location: login.php");
            echo ("Du är inte inloggad");
        }
    }
    else
    {
        echo "\$_POST['username'] does not exist<br>Can not loggin";
    }
}
else
{
    echo "\$_SESSION['username'] exists. Already logged in?<br>";
}
?>

Thanks! Got this:

Parse error: syntax error, unexpected 'if' (T_IF), expecting ',' or ';' in C:\xampp\htdocs\film\login.php on line 15

Ch0cu3r · January 9, 2014

Oops, change

echo "Attempting to login....<br>"

to

echo "Attempting to login....<br>";

I left the semi-colon off of the end of line 13 which is causing the error. Try to login again and post the messages you get.

carophp · January 9, 2014

Now we're talking, but still i'm not logged in!

Attempting to login....

$_SESSION['username'] exists. Already logged in?

Ch0cu3r · January 9, 2014

The session data still exists from the last loggin. This is because your logout code is not removing the session correctly, use session_destroy() for this instead.

To test your code add session_destroy() after session_start() now run your code. Remove session_destory() after you have ran the code, this to clear the sessions of any data.

carophp · January 9, 2014

So it's something wrong with my query?

Attempting to login....
$_POST['username'] does not exist
Can not loggin

Ch0cu3r · January 9, 2014

Are you entering the username and password in your login form? Could you post the login form too

carophp · January 9, 2014

Comes here! (sorry I thought I posted the whole file already!)

I have 3 users and tried them all, one with MD5 encryption password and two user without. None working..

<?php
session_start();
//Om användaren har tryck på loggut-knappen så verkställs sessionen.






if ($_GET['action']=='logout') {
 // session_destroy();
}


/*


if (isset($_GET['action']===true && $_GET['action'] =='logout') {
// logga ut
session_destroy();
}




if (isset($_POST['action']=='logout')) {
 // logga ut 
 session_unset();
}


*/
if (! isset($_SESSION['username'])) {


 if (isset($_POST['username'])) {
$username = addslashes($_POST['username']); 


$pswd = addslashes($_POST['pswd']);


/*Här försöker vi koppla upp mot databasen*/
mysql_connect('localhost', 'root', '')
 or die("Kan inte koppla upp mot db-servern");
mysql_select_db("db_film")
 or die("Kan inte koppla upp mot db");


/*Här hämtas namn, användarnamn och lösenord från tabellen users i databasen.  Om de inskrivna värdena stämmer överens med uppgifterna i          databasen så skickas vi till publishpost.php. */
$query = "SELECT `username`, `pswd` FROM `users` WHERE username='$username' AND pswd=md5('$pswd')";
echo "<pre>$query</pre>";
$result = mysql_query($query) or die( mysql_error() );
$result = mysql_query($query);
if (mysql_num_rows($result) == 1){
 $_SESSION['firstname'] = mysql_result($result,0,"firstname");
 $_SESSION['username'] = mysql_result($result,0,"username");
 $user = $_POST['username'];
 $salt = "somestring";
 $_SESSION['token'] = md5($salt . $user . $salt);
 $token = $_SESSION['token'];
 header("location: publishpost.php");


}
/*Om uppgifterna inte stämmer så stannar användaren kvar på login.php och en text skrivs ut som talar om 
att man inte har blivit inloggad.*/
else 
{
$username = $_SESSION['username'];
header("location: login.php");
echo ("Du är inte inloggad");
} 
 }
} 






?><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="sv">
<head>
<!--  FILM -->
<title></title>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1" />
<link rel="stylesheet" type="text/css" href="style.css" />
</head>
<body>






 <div id="header">
Välkommen!
<a href="viewpost.php">Läs poster</a>  
</div>


<div id="container">
<?php include 'register.php'; ?>




<form method="post" action="<?php echo $_SERVER['PHP_SELF'];?>">
  <p>Användarnamn<br /><input type="text" name="username" /></p>
  <p>Lösenord<br /><input type="password" name="pswd" /></p>


  <p><input type="submit" value="Logga in" /></p>
  
</form>


<a href="login.php?action=logout">Logga ut</a> 


  
</div>
</body>
</html>

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Unable to login (PHP & mySQL

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