nisroc Posted January 11, 2014 Share Posted January 11, 2014 $query_TopNumbers = "SELECT Number1, COUNT(Number1) AS CT FROM Draws GROUP BY Number1 ORDER BY COUNT(Number1) DESC"; I am curious if it is possible to set up "Number1" in the query to be dynamic. i need to count off the columns and the count repeating values which the query is doing. I have 6 columns, Number1, Number2, Number3, Number4, Number5, Number6. Is it possible to make a query such as "SELECT Number . $colNumber, COUNT(Number . $colNumber) AS CT FROM Draws GROUP BY Number . $colNumber ORDER BY COUNT(Number . $colNumber) DESC"; and just loop it? or is there an easier way. I need the results in a table. Quote Link to comment https://forums.phpfreaks.com/topic/285293-quick-question/ Share on other sites More sharing options...
Psycho Posted January 11, 2014 Share Posted January 11, 2014 Don't run queries in loops. based upon your sample query you just want a count of each column that has values. Try this SELECT COUNT(Number1) AS CT1, COUNT(Number2) AS CT2, COUNT(Number3) AS CT3, COUNT(Number4) AS CT4, COUNT(Number5) AS CT5, COUNT(Number6) AS CT6 FROM Draws Quote Link to comment https://forums.phpfreaks.com/topic/285293-quick-question/#findComment-1464879 Share on other sites More sharing options...
nisroc Posted January 11, 2014 Author Share Posted January 11, 2014 thank you very much Quote Link to comment https://forums.phpfreaks.com/topic/285293-quick-question/#findComment-1464882 Share on other sites More sharing options...
Barand Posted January 11, 2014 Share Posted January 11, 2014 I believe he wants counts of the occurences of each number SELECT colno, num, COUNT(*) AS CT FROM ( SELECT 1 as colno, Number1 as num FROM Draws UNION SELECT 2 as colno, Number2 as num FROM Draws UNION SELECT 3 as colno, Number3 as num FROM Draws UNION SELECT 4 as colno, Number4 as num FROM Draws UNION SELECT 5 as colno, Number5 as num FROM Draws UNION SELECT 6 as colno, Number6 as num FROM Draws ) as balls GROUP BY colno, num ORDER BY colno, CT DESC Quote Link to comment https://forums.phpfreaks.com/topic/285293-quick-question/#findComment-1464883 Share on other sites More sharing options...
nisroc Posted January 12, 2014 Author Share Posted January 12, 2014 (edited) I spent time trying to get it to work ... both example however nothing so I will try explain myself a little better. I am trying to learn PhP/MySQL by creating a lotto script that shows the most numbers drawn currently in each column. The lotto is drawn with 7 numbers one being a bonus number (do not need for this query). My table is populated with columns ID, Date, Number1 to Number6 and Bonus. My idea is to take Number1 col and find out the most called numbers from top to bottom in it and list them in a table which i have accomplished. However I got stuck when i wanted to do the same thing for Number2 to Number 6 (including Number1) all in one query. with what i have before i added anything else the results came out like this for column Number1 1st number # 1 371 2 330 4 295 3 290 5 226 ... 38 1 i just wish to do the same thing with number1 though number6 and add them to one HTML table. PS thank for the ideas... playing with them taught me more about things i did not understand correctly Edited January 12, 2014 by nisroc Quote Link to comment https://forums.phpfreaks.com/topic/285293-quick-question/#findComment-1464953 Share on other sites More sharing options...
Barand Posted January 12, 2014 Share Posted January 12, 2014 In my query, change all "UNION" to "UNION ALL" Quote Link to comment https://forums.phpfreaks.com/topic/285293-quick-question/#findComment-1464956 Share on other sites More sharing options...
nisroc Posted January 12, 2014 Author Share Posted January 12, 2014 (edited) SELECT colno, num, COUNT(*) AS CT FROM ( SELECT 1 as colno, Number1 as num FROM Draws UNION ALL SELECT 2 as colno, Number2 as num FROM Draws UNION ALL SELECT 3 as colno, Number3 as num FROM Draws UNION ALL SELECT 4 as colno, Number4 as num FROM Draws UNION ALL SELECT 5 as colno, Number5 as num FROM Draws UNION ALL SELECT 6 as colno, Number6 as num FROM Draws ) as balls GROUP BY colno, num ORDER BY colno, CT DESC"; error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '"' at line 17 nvm dumb and blind i got it Edited January 12, 2014 by nisroc Quote Link to comment https://forums.phpfreaks.com/topic/285293-quick-question/#findComment-1464961 Share on other sites More sharing options...
nisroc Posted January 12, 2014 Author Share Posted January 12, 2014 This now works but with a problem of the table. everything is listed in 2 columns and i would like to list it as <table> <tr> <td>Number1</td><td>#</td> <td>Number2</td><td>#</td> <td>Number3</td><td>#</td> <td>Number4</td><td>#</td> <td>Number5</td><td>#</td> <td>Number6</td><td>#</td> </tr> </table> this is my current table code <table border="0"> <tr> <td>1st number</td> <td>#</td> </tr> <?php do { ?> <tr> <td><?php echo $row_TopNumbers['num']; ?></td> <td><?php echo $row_TopNumbers['CT']; ?></td> </tr> <?php } while ($row_TopNumbers = mysql_fetch_assoc($TopNumbers)); ?> </table> Quote Link to comment https://forums.phpfreaks.com/topic/285293-quick-question/#findComment-1464965 Share on other sites More sharing options...
Barand Posted January 12, 2014 Share Posted January 12, 2014 try $sql = "SELECT colno, num, COUNT(*) AS CT FROM ( SELECT 1 as colno, Number1 as num FROM Draws UNION ALL SELECT 2 as colno, Number2 as num FROM Draws UNION ALL SELECT 3 as colno, Number3 as num FROM Draws UNION ALL SELECT 4 as colno, Number4 as num FROM Draws UNION ALL SELECT 5 as colno, Number5 as num FROM Draws UNION ALL SELECT 6 as colno, Number6 as num FROM Draws ) as balls GROUP BY colno, num ORDER BY num, colno"; echo "<h3>Frequency table</h3> <table border='1' style='border-collapse:collapse'> <tr><th></th><th>Number1</th><th>Number2</th><th>Number3</th><th>Number4</th><th>Number5</th><th>Number6</th></tr>\n"; $res = $db->query($sql); $currNum = 0; while (list($col,$num,$ct) = $res->fetch_row()) { if ($num != $currNum) { if ($currNum) { echo "<tr><th>$currNum</th><td>" . join('</td><td>',$freqs) . "</td></tr>\n"; } $freqs = array_fill_keys(range(1,6),0); $currNum = $num; } $freqs[$col] = $ct; } echo "<tr><th>$currNum</th><td>" . join('</td><td>',$freqs) . "</td></tr>\n"; echo "</table>\n" Quote Link to comment https://forums.phpfreaks.com/topic/285293-quick-question/#findComment-1464977 Share on other sites More sharing options...
nisroc Posted January 12, 2014 Author Share Posted January 12, 2014 (edited) No go trying to figure out a error; Fatal error: Call to a member function query() on a non-object in D:\xampp\htdocs\test.php on line 51 Before you gave me this idea i was working on a if else theory but needed to change colno to rownum. I am not sure rownum would have worked the same way with the sql <?php require_once('Connections/Lotto.php'); ?> <?php if (!function_exists("GetSQLValueString")) { function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "") { if (PHP_VERSION < 6) { $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue; } $theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue); switch ($theType) { case "text": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "long": case "int": $theValue = ($theValue != "") ? intval($theValue) : "NULL"; break; case "double": $theValue = ($theValue != "") ? doubleval($theValue) : "NULL"; break; case "date": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "defined": $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue; break; } return $theValue; } } mysql_select_db($database_Lotto, $Lotto); $sql = "SELECT colno, num, COUNT(*) AS CT FROM ( SELECT 1 as colno, Number1 as num FROM Draws UNION ALL SELECT 2 as colno, Number2 as num FROM Draws UNION ALL SELECT 3 as colno, Number3 as num FROM Draws UNION ALL SELECT 4 as colno, Number4 as num FROM Draws UNION ALL SELECT 5 as colno, Number5 as num FROM Draws UNION ALL SELECT 6 as colno, Number6 as num FROM Draws ) as balls GROUP BY colno, num ORDER BY num, colno; "; $Recordset1 = mysql_query($sql, $Lotto) or die(mysql_error()); $row_Recordset1 = mysql_fetch_assoc($Recordset1); $totalRows_Recordset1 = mysql_num_rows($Recordset1); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <?php echo "<h3>Frequency table</h3> <table border='1' style='border-collapse:collapse'> <tr><th></th><th>Number1</th><th>Number2</th><th>Number3</th><th>Number4</th><th>Number5</th><th>Number6</th></tr>\n"; $res = $database_Lotto->query($sql); $currNum = 0; while (list($col,$num,$ct) = $res->fetch_row()) { if ($num != $currNum) { if ($currNum) { echo "<tr><th>$currNum</th><td>" . join('</td><td>',$freqs) . "</td></tr>\n"; } $freqs = array_fill_keys(range(1,6),0); $currNum = $num; } $freqs[$col] = $ct; } echo "<tr><th>$currNum</th><td>" . join('</td><td>',$freqs) . "</td></tr>\n"; echo "</table>\n" ?> </body> </html> <?php mysql_free_result($Recordset1); ?> Edited January 12, 2014 by nisroc Quote Link to comment https://forums.phpfreaks.com/topic/285293-quick-question/#findComment-1464989 Share on other sites More sharing options...
Barand Posted January 12, 2014 Share Posted January 12, 2014 you need to define the mysqli $db object first $db = new mysqli(HOST,USERNAME,PASSWORD,DATABASE); // use your credentials Quote Link to comment https://forums.phpfreaks.com/topic/285293-quick-question/#findComment-1464991 Share on other sites More sharing options...
nisroc Posted January 12, 2014 Author Share Posted January 12, 2014 you need to define the mysqli $db object first $db = new mysqli(HOST,USERNAME,PASSWORD,DATABASE); // use your credentials tried and worked! Thanks but why would it not work with my include credentials? The include at very top of the file holds hosts, user, pass and db info Quote Link to comment https://forums.phpfreaks.com/topic/285293-quick-question/#findComment-1464992 Share on other sites More sharing options...
Barand Posted January 12, 2014 Share Posted January 12, 2014 Because you were using mysql which is deprecated. I am using mysqli (as you should be) Quote Link to comment https://forums.phpfreaks.com/topic/285293-quick-question/#findComment-1464993 Share on other sites More sharing options...
nisroc Posted January 12, 2014 Author Share Posted January 12, 2014 Because you were using mysql which is deprecated. I am using mysqli (as you should be) ah I stop doing that. Thanks again for all your help Quote Link to comment https://forums.phpfreaks.com/topic/285293-quick-question/#findComment-1464994 Share on other sites More sharing options...
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