aryan99 Posted January 16, 2014 Share Posted January 16, 2014 Hi ! I from Iran and Excusme If I writeing very bad In Facemash Script I may : When for second I go to " install_images.php " the Previous picture not again write New Image In Database! becuse when I go to " install_images.php " for second the Previous picture for again write in database new !!!! What to do (PHP Code) ? Link to comment https://forums.phpfreaks.com/topic/285401-answer-me-please-facemash/ Share on other sites More sharing options...
broxi000 Posted January 16, 2014 Share Posted January 16, 2014 The problem is when you enter to "install_images.php" for first time , the image is written on Database , and when you do this twice the image is re-written on Database ? Isn't it ? Link to comment https://forums.phpfreaks.com/topic/285401-answer-me-please-facemash/#findComment-1465373 Share on other sites More sharing options...
aryan99 Posted January 16, 2014 Author Share Posted January 16, 2014 yes this is - but when for twice the images added - means ==> In addition to Previous picture + new picture - means ==> 2 picture as one :-?? TNX Link to comment https://forums.phpfreaks.com/topic/285401-answer-me-please-facemash/#findComment-1465375 Share on other sites More sharing options...
aryan99 Posted January 16, 2014 Author Share Posted January 16, 2014 ؟؟؟؟؟؟ Link to comment https://forums.phpfreaks.com/topic/285401-answer-me-please-facemash/#findComment-1465378 Share on other sites More sharing options...
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