aryan99 Posted January 16, 2014 Share Posted January 16, 2014 (edited) Hi ! I from Iran and Excusme If I writeing very bad In Facemash Script I may : When for second I go to " install_images.php " the Previous picture not again write New Image In Database! becuse when I go to " install_images.php " for second the Previous picture for again write in database new !!!! What to do (PHP Code) ? Edited January 16, 2014 by aryan99 Quote Link to comment Share on other sites More sharing options...
broxi000 Posted January 16, 2014 Share Posted January 16, 2014 (edited) The problem is when you enter to "install_images.php" for first time , the image is written on Database , and when you do this twice the image is re-written on Database ? Isn't it ? Edited January 16, 2014 by broxi000 Quote Link to comment Share on other sites More sharing options...
aryan99 Posted January 16, 2014 Author Share Posted January 16, 2014 (edited) yes this is - but when for twice the images added - means ==> In addition to Previous picture + new picture - means ==> 2 picture as one :-?? TNX Edited January 16, 2014 by aryan99 Quote Link to comment Share on other sites More sharing options...
aryan99 Posted January 16, 2014 Author Share Posted January 16, 2014 ؟؟؟؟؟؟ Quote Link to comment Share on other sites More sharing options...
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