bickyz Posted February 1, 2014 Share Posted February 1, 2014 Hi I am trying to create a php page that pulls data from MSSQL table. Following is the code I am using: <?php $objConnect = mssql_connect("localhost","sa",""); $objDB = mssql_select_db("mydatabase"); $strSQL = "SELECT * FROM tblPC ORDER BY pc_name ASC"; $objQuery = mssql_query($strSQL) or die ("Error Query [".$strSQL."]"); $Num_Rows = mssql_num_rows($objQuery); $Per_Page = 20; // Per Page $Page = $_GET["Page"]; if(!$_GET["Page"]) { $Page=1; } $Prev_Page = $Page-1; $Next_Page = $Page+1; $Page_Start = (($Per_Page*$Page)-$Per_Page); if($Num_Rows<=$Per_Page) { $Num_Pages =1; } else if(($Num_Rows % $Per_Page)==0) { $Num_Pages =($Num_Rows/$Per_Page) ; } else { $Num_Pages =($Num_Rows/$Per_Page)+1; $Num_Pages = (int)$Num_Pages; } $Page_End = $Per_Page * $Page; IF ($Page_End > $Num_Rows) { $Page_End = $Num_Rows; } ?> <table width="600" border="1"> <tr> <th width="20%">PC ID</th> <th width="40%">PC Name</th> <th width="20%">Make</th> <th width="20%">Room</th> </tr> <?php for($i=$Page_Start;$i<$Page_End;$i++) { ?> <tr> <td><?=mssql_result($objQuery,$i,"pc_id");?></td> <td><?=mssql_result($objQuery,$i,"pc_name");?></td> <td><?=mssql_result($objQuery,$i,"makemodel");?></td> <td><?=mssql_result($objQuery,$i,"room_id");?></td> </tr> <?php } ?> </table> <br> Total <?= $Num_Rows;?> Record : <?=$Num_Pages;?> Page : <?php if($Prev_Page) { echo " <a href='$_SERVER[SCRIPT_NAME]?Page=$Prev_Page'><< Back</a> "; } for($i=1; $i<=$Num_Pages; $i++){ if($i != $Page) { echo "[ <a href='$_SERVER[SCRIPT_NAME]?Page=$i'>$i</a> ]"; } else { echo "<b> $i </b>"; } } if($Page!=$Num_Pages) { echo " <a href ='$_SERVER[SCRIPT_NAME]?Page=$Next_Page'>Next>></a> "; } mssql_close($objConnect); ?> tblPC pc_idpc_namemakemodelroom_id tblROOMroom_id room_name building The room_id field on tblPC and tblRoom are in database relationship. I have following function that obtains room name from tblROOM. How can I use this function in the above page so that room_id on <td><?=mssql_result($objQuery,$i,"room_id");?></td> will display the room name instead of the id. function ObtainRoomName($identifier) { global $objDB, $objConnect; mssql_select_db($objDB, $objConnect); $query_rsfunction = sprintf("SELECT tblROOM.room_name FROM tblROOM WHERE tblROOM.room_id = %s", $identifier); $rsfunction = mssql_query($query_rsfunction, $objConnect) or die("Couldn't connect to SQL Server on $objDB"); $row_rsfunction = mssql_fetch_assoc($rsfunction); $totalRows_rsfunction = mssql_num_rows($rsfunction); return $row_rsfunction['room_name']; mssql_free_result($rsfunction); } I have use this functuin with my other project by using <?php echo ObtainRoomName($row_rs1['room_id']); ?> but here Im lost with <?=mssql_result($objQuery,$i,"room_id");?> Any help would be much appreciated, thank you. Quote Link to comment Share on other sites More sharing options...
Barand Posted February 1, 2014 Share Posted February 1, 2014 The last thing you want to do is query one table then, as you process that table's records, run a separate query on each record. Do not run queries in loops, use a JOIN instead. You first query should be SELECT p.pc_id, p.pc_name, p.makemodel, r.room_name, r.building FROM tblpc as p INNER JOIN tblroom as r USING (room_id) ORDER BY p.pc_name By using a join it finds the matching room record using the room_id and you can get the room name and building in the one query Quote Link to comment Share on other sites More sharing options...
bickyz Posted February 2, 2014 Author Share Posted February 2, 2014 hi barand, thank you for looking at it. The above query throws following error Msg 102, Level 15, State 1, Line 3 Incorrect syntax near 'USING'. I am using MS SQL server. Quote Link to comment Share on other sites More sharing options...
Barand Posted February 2, 2014 Share Posted February 2, 2014 Sorry, I forgot you were usinf MSSQL and not MySQL. Use SELECT p.pc_id, p.pc_name, p.makemodel, r.room_name, r.building FROM tblpc as p INNER JOIN tblroom as r ON p.room_id = r.room_id ORDER BY p.pc_name Quote Link to comment Share on other sites More sharing options...
bickyz Posted February 2, 2014 Author Share Posted February 2, 2014 thank you very much Barand Quote Link to comment Share on other sites More sharing options...
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