FUNKAM35 Posted February 24, 2014 Share Posted February 24, 2014 $total_results = mysql_result(mysql_query("SELECT COUNT(*) as Num FROM rental WHERE $where "),0) ; $total_pages = ceil($total_results/$max_results); if ($total_results > $max_results) { if(!isset($_GET['page'])){ $page = 1; } else { $page2 = $_GET['page']; } $from =(($page * $max_results) - $max_results ); } if($page2>1) { $pages="Page $page2 of $total_pages"; } Hi, I have added the above code and it works fine except I get this error Notice: Undefined Variable $pages I only get this error on page 1 where it doesn't show page 1 of x as I don't want it to show page 1 of x no errors on eg page 2 of x only on page 1 I think because the pages is empty but don't know how to fix this Any help would be appreciated Quote Link to comment https://forums.phpfreaks.com/topic/286474-notice-undefined-variable/ Share on other sites More sharing options...
paddy_fields Posted February 24, 2014 Share Posted February 24, 2014 $total_results = mysql_result(mysql_query("SELECT COUNT(*) as Num FROM rental WHERE $where "),0) ; $total_pages = ceil($total_results/$max_results); if ($total_results > $max_results) { if(!isset($_GET['page'])){ $page = 1; } else { $page2 = $_GET['page']; } $from =(($page * $max_results) - $max_results ); } if($page2>1) { $pages="Page $page2 of $total_pages"; } else { $pages="Page $page of $total_pages"; } Quote Link to comment https://forums.phpfreaks.com/topic/286474-notice-undefined-variable/#findComment-1470399 Share on other sites More sharing options...
Solution FUNKAM35 Posted February 24, 2014 Author Solution Share Posted February 24, 2014 $total_results = mysql_result(mysql_query("SELECT COUNT(*) as Num FROM rental WHERE $where "),0) ; $total_pages = ceil($total_results/$max_results); if ($total_results > $max_results) { if(!isset($_GET['page'])){ $page = 1; } else { $page2 = $_GET['page']; $from =(($page * $max_results) - $max_results ); } if($page>1) { $pages="Page $page of $total_pages"; } else { $pages=""; } } Thanks Paddyfields, this didn't quite work but pointed me in the right direction and this code did work: Quote Link to comment https://forums.phpfreaks.com/topic/286474-notice-undefined-variable/#findComment-1470405 Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.