Get current page from an included PHP script

[skania]

So I have a tedious status selection bar that is on every page, so I simply used an include on the pages, the actual navigation bar separated.

 

The navigation is ~/public_html/courseListMenu.php

 

 

When the user is on a certain page, it will simply refresh the page to the current page, which the updated status (courseID), and the information about that course.

However, if the user is looking at a participant, and clicks on the navigation (ie, change the courseID, thus changing the catalog of people in it), I want to redirect to the index.php.

 

 

 

So here is the problem:

 

I have a URL, www.example.com/atn/index.php

 

*A class is selected*

 

New URL with updated page, www.example.com/atn/index.php?CRN=999999999

 

Select editparticipant, www.example.com/atn/editparty.php?CRN=999999999&PARTY=111111111

 

*A new class is selected*

 

I need to extract "editparty.php" so I can compare the string and if they match, then revert the user back to index.php.

I need to compare strings, because since this is an include, there will be other pages that will redirect the user to index.php

 

The exact problem I have is that I can get the script that is running, but it is the INCLUDED script filename, not the file name it is INCLUDED on, which is the filename I need.

 

 

I hope this is clear; if it isn't, I can try to explain a little better.

 

If anyone has any idea on how I can get this, it would be very much appreciated!

Edited February 24, 2014 by skania

[.josh]

 

 

test.php

<?php
echo "from test.php";
print_r($_SERVER);
include('test2.php');
?>

test2.php

<?php
echo "from test2.php";
print_r($_SERVER);
?>

both print_r($_SERVER) will show:

 

Array
(
    [SCRIPT_FILENAME] => /path/to/script/test.php
    [REQUEST_URI] => /test.php
    [SCRIPT_NAME] => /test.php
    [PHP_SELF] => /test.php
)