dannerz Posted March 2, 2014 Share Posted March 2, 2014 (edited) echo "you bought 1 archer"; $data = mysql_query("SELECT Vals FROM vals2 WHERE ValsN = 'archers'"); if ($data == false) exit("This has failed"); $msg = mysql_fetch_assoc($data); echo "<br />"; echo $msg;//this just says that it is an array echo "<br />"; echo $data; echo "<br />"; $msg2 = mysql_num_fields($data); echo $msg2; echo "<br />"; $msg3 = mysql_fetch_row($data);//this is not shown for some reason echo $msg3; This is the code. I'd like to get a number out of the db, and convert the resource into just a number value or string, then alter the number in PHP (i know how to do that part) then put the number back into the db (I think I can do that also) I just don't know how to convert a resource ("$data") into a variable to use in the PHP code. Hopefully you know what I mean. (the output of the above code is) Shop choice method. you bought 1 archer Array Resource id #4 1 Edited March 2, 2014 by dannerz Quote Link to comment Share on other sites More sharing options...
Solution Barand Posted March 2, 2014 Solution Share Posted March 2, 2014 have a look at the example in the manual http://uk1.php.net/manual/en/function.mysql-fetch-assoc.php Quote Link to comment Share on other sites More sharing options...
dannerz Posted March 2, 2014 Author Share Posted March 2, 2014 (edited) I'll start copy pasting and editing (thanks) Edited March 2, 2014 by dannerz Quote Link to comment Share on other sites More sharing options...
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