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I have 3 tables im working with

 

sab_merc (job table)

-id

-username

-service

-job_desc

 

Users (user table)

-id

-username

-other misc info

 

onjob_sab (theis in the x-ref table in a many to many relationship)

-user_id

-job_id

 

 

select  from onjob_sab left join sab_merc on(onjob_sab.user_id = sab_merc.id) where (onjob_sab.user_id != '1')

 

what I get from this query is all the open jobs that user 1 is not part of.

 

Now since multiple people can can be on multiple jobs I get a query that repeats the jobs for each users on them

2     chris     sextreme69     AIM     Stryker_     http://www.kingsofchaos.com/stats.php?id=3012255     Elves     1     Gold     500000     0           11.13.05     1131940811     open     2     1
2     chris     sextreme69     AIM     Stryker_     http://www.kingsofchaos.com/stats.php?id=3012255     Elves     1     Gold     500000     0           11.13.05     1131940811     open     2     3
4     workwarnings     testee     MSN     Steeringwhell     http://www.kingsofchaos.com/stats.php?id=3009074     Elves     5     Gold     78552     0           11.15.05     1132116959     open     4     4
4     workwarnings     testee     MSN     Steeringwhell     http://www.kingsofchaos.com/stats.php?id=3009074     Elves     5     Gold     78552     0           11.15.05     1132116959     open     4     5

 

All I really want from this query is to fin all jobs that user 1 is not assiged too and them display them in a "while loop" using php.

 

So in the example you can see that there is really only 2 jobs available that user 1 is not assiged too, but they get repeated since there is already other users on those jobs.

 

Hope this makes sense

 

Thanks in advance,

Chris

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