holly9 Posted April 30, 2014 Share Posted April 30, 2014 hi i have a php site and i want to have a sitemap on my site.i have seen all kinds of site map which is confusing because i don't know which is the best to use and if any sitemap can be used with ajax live search.i don't want to make two sitemaps so i hope that a rss feed sitemap is enough to help search engines crawl my site.i want a rss feed to let people subscribe .is it a good idea to put disallow in robot.txt for sitemap? some people said that they need to do that to prevent content theft or something like that.thanks i want to use a sitemap like this: <?xml version="1.0" encoding="UTF-8" ?> <rss version="2.0"> <channel> <title>W3Schools Home Page</title> <link>http://www.w3schools.com</link> <description>Free web building tutorials</description> <item> <title>RSS Tutorial</title> <link>http://www.w3schools.com/rss</link> <description>New RSS tutorial on W3Schools</description> </item> <item> <title>XML Tutorial</title> <link>http://www.w3schools.com/xml</link> <description>New XML tutorial on W3Schools</description> </item> </channel> </rss> i saw this livesearch code at w3schools: <html> <head> <script> function showResult(str) { if (str.length==0) { document.getElementById("livesearch").innerHTML=""; document.getElementById("livesearch").style.border="0px"; return; } if (window.XMLHttpRequest) { // code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else { // code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("livesearch").innerHTML=xmlhttp.responseText; document.getElementById("livesearch").style.border="1px solid #A5ACB2"; } } xmlhttp.open("GET","livesearch.php?q="+str,true); xmlhttp.send(); } </script> </head> <body> <form> <input type="text" size="30" onkeyup="showResult(this.value)"> <div id="livesearch"></div> </form> </body> </html> this will get data for live search: <?php $xmlDoc=new DOMDocument(); $xmlDoc->load("links.xml"); $x=$xmlDoc->getElementsByTagName('link'); //get the q parameter from URL $q=$_GET["q"]; //lookup all links from the xml file if length of q>0 if (strlen($q)>0) { $hint=""; for($i=0; $i<($x->length); $i++) { $y=$x->item($i)->getElementsByTagName('title'); $z=$x->item($i)->getElementsByTagName('url'); if ($y->item(0)->nodeType==1) { //find a link matching the search text if (stristr($y->item(0)->childNodes->item(0)->nodeValue,$q)) { if ($hint=="") { $hint="<a href='" . $z->item(0)->childNodes->item(0)->nodeValue . "' target='_blank'>" . $y->item(0)->childNodes->item(0)->nodeValue . "</a>"; } else { $hint=$hint . "<br /><a href='" . $z->item(0)->childNodes->item(0)->nodeValue . "' target='_blank'>" . $y->item(0)->childNodes->item(0)->nodeValue . "</a>"; } } } } } // Set output to "no suggestion" if no hint were found // or to the correct values if ($hint=="") { $response="no suggestion"; } else { $response=$hint; } //output the response echo $response; ?> Link to comment https://forums.phpfreaks.com/topic/288135-can-a-rss-feed-sitemap-be-used-with-ajax-live-search/ Share on other sites More sharing options...
Recommended Posts
Archived
This topic is now archived and is closed to further replies.