Making a variable name with partial use of another variable

[Phaelon]

Does anyone know how I can make a variable name with partial use of another variable?

while ($row = mysql_fetch_assoc($result)) {
    $option'.$row['number'].' = 1;
}

So, I would get:

$option1 = 1
$option2 = 1
$option3 = 1

I tried '$option'.$row['number'].'' = 1;, but it didn't work.

[mac_gyver]

making a series of numbered variables creates a nightmare of extra code.

 

you need to use a simple array - $option[1], $option[2], ...

[Phaelon]

No, I want to do it my way because there is a bigger picture to what I am doing which I haven't explained as it is irrelevant and I want to keep my thread simple.

 

... So do you know if what I want to do can be done, or are you just lecture me on what you thinks best without providing any assistance what so ever?

Edited May 12, 2014 by Phaelon

[Phaelon]

What ever man...

 

For anyone that wants to know the answer, here it is:

 

while ($row = mysql_fetch_assoc($result)) {
    ${option'.$row['number']} = 1;
}

[mac_gyver]

no one here really wants to see code you got at another help site.

 

btw - that code is three times slower than the method i suggested, which is just one of the problems with using variable variables.

[Phaelon]

Sure they don't.

 

The code you suggested isn't compatible with what I needed to do. I already told you this.

You need to stop assuming you know other people are trying to do.. and if speeds anything to go by, I'd still be stuck if it wasn't for the other help site.

 

You need to stop over analysing in life. I use to have this problem.

 

 

Cheers.

Edited May 12, 2014 by Phaelon

[Jacques1]

And now you have two problems: utter ignorance and a bunch of crap code.

[Phaelon]

No, I have a working product.

[Ch0cu3r]

And now you have two problems: utter ignorance and a bunch of crap code.

Agreed..

 

FYI this is what the OP is trying to achieve

http://forums.phpfreaks.com/topic/288403-creating-a-single-variable-for-multiple-mysql-returns-of-the-same-data/