Kieran_Smith Posted May 20, 2014 Share Posted May 20, 2014 Im having issues with logging out of a my website. I have successfully managed to log in. I am using sessions to do it and have been using session_unregister, which I believe is not depreciated. I have tried using unset but I am now getting the error Parse error: syntax error, unexpected '"authenticatedUser"' (T_CONSTANT_ENCAPSED_STRING) in C:\wamp\www\ShreddedNutrition\HTML\Logout.php on line 8 this is my log out code <?php session_start(); $appUsername = $_SESSION["authenticatedUser"]; $_SESSION["message"] = "You Have Logged out"; unset("authenticatedUser"); // Relocate back to the login page header("Location: Login.php"); //session_destroy(); ?> and this is to log in <?php include 'db.inc'; session_start(); $UserEmail =$_POST["EmailAddress"]; $UserPassword =$_POST["Password"]; $query = "SELECT * FROM members WHERE EmailAddress = '$UserEmail' AND password = '$UserPassword' "; $connection = mysql_connect($hostname, $username, $password) or die ("Unable to connect!"); mysql_select_db($databaseName) or die ("Unable to select database!"); $result = mysql_query($query) or die ("Error in query: $query. ".mysql_error()); // see if any rows were returned if (mysql_num_rows($result) > 0) { $_SESSION["authenticatedUser"] = $UserEmail; // Relocate to the logged-in page header("Location: Index.php"); } else { $_SESSION["message"] = "Could not connect log in as $UserEmail " ; header("Location: Login.php"); } mysql_free_result($result); mysql_close($connection); ?> Link to comment https://forums.phpfreaks.com/topic/288629-loggin-out-issues/ Share on other sites More sharing options...
IanA Posted May 20, 2014 Share Posted May 20, 2014 Try unset($_SESSION["authenticatedUser"]); Link to comment https://forums.phpfreaks.com/topic/288629-loggin-out-issues/#findComment-1480178 Share on other sites More sharing options...
Recommended Posts
Archived
This topic is now archived and is closed to further replies.