ScottWilson Posted May 23, 2014 Share Posted May 23, 2014 I have this code: <td><form action="" method="post" name="TableData" class="style5" id="TableData"> <table width="800" border="0" bordercolor="#000000" background="Assets/Tablebar.gif"> <!--DWLayoutTable--> <tr> <td width="183" height="20" align="center"><div align="center" class="style11 style1"></div></td> <td width="317" align="center"><div align="center" class="style11"><span class="style2"><?php echo $row_TableData['UserID']; ?></span></div></td> <td width="136" align="center"><div align="center" class="style11"><span class="style2"><?php echo $row_TableData['UserName']; ?></span></div></td> <td width="136" align="center"><div align="center" class="style2 style11"><span class="style11"><span class="style2"><?php echo $row_TableData['Score']; ?></span></span></div></td> <td width="103" align="center" valign="top"><span class="style2 style11"> <?php for($i = 0; $i < $row_TableData['TourWins']; $i++) { echo '<img src="Assets/Medal.gif" />'; }?> </span></td> </tr> </table> </form> </td> The Table displays fine and it sorts fine win Highest to lowest score, I am wanting to put place numbers Like 1,2,3,4 etc in the first Colom which is in bold, but I don't know what to use. any help would be great. Quote Link to comment Share on other sites More sharing options...
ScottWilson Posted May 23, 2014 Author Share Posted May 23, 2014 I tried this $count = 1;echo $count++; But it just displays 1 in every row. Quote Link to comment Share on other sites More sharing options...
Solution Ch0cu3r Posted May 23, 2014 Solution Share Posted May 23, 2014 I tried this $count = 1; echo $count++; But it just displays 1 in every row. That is what you need. Just make sure $count = 1; is outside of the loop! Otherwise it will reset the counter on each iteration Quote Link to comment Share on other sites More sharing options...
ScottWilson Posted May 23, 2014 Author Share Posted May 23, 2014 OK ive placed the code and it counts fine bar the first which has the Stack error box in? am i placing the $count = 1; in the wrong place Ive placed the other part in the table cell? Quote Link to comment Share on other sites More sharing options...
ScottWilson Posted May 23, 2014 Author Share Posted May 23, 2014 ah fixed it cheers Quote Link to comment Share on other sites More sharing options...
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