checkbox

[rafal]

hallo everybody,

i have column in my guestbook table mysql database names vis.

i want make it possible for user to make theier comments invisible.

if user checked yes, the comment will be viewd. if he did not checked, the comment will not be viewed.

in my visibility.php the user can later change the value from yes to no or from no to yes.

i do not know how to make this possible in update.php file.

thank you very much for your help.

Rafal

 

here is my code which not work in visibility.php

<form action="update.php" method="post">
<input type="hidden" name="inp_id" value="<?php echo  $row[id) ?>">
visible: <input type="checkbox" name="inp_vis" <?php if ($row[vis] == "yes") { echo "value='yes' checked"; } else { echo "value='no'"; } ?>>
<br>
<input type="submit" value="Save">
</form>

Edited September 25, 2014 by rafal

[CroNiX]

Checkboxes will only be transmitted if they are actually checked, so just check to see if it isset().

$checked = isset($_POST['inp_vis']);

[Psycho]

As to your code, you do not change the value of the checkbox. And, in this case the value really isn't important. The checkbox should use the same value and you should check/uncheck it based upon the saved data. Also, you should save the value as a numeric equivalent of a Boolean, i.e. 0 (false) or 1 (true).

 

 

visible: <input type="checkbox" name="inp_vis" value="visible" <?php echo if ($row['vis']) "checked='checked'"; ?>>

[rafal]

Thank you dear CroNiX.

 

dear Psycho, Thank you, i entered your code but i got this error:

Parse error: syntax error, unexpected 'if' (T_IF) in update.php on line 92

[rafal]

thank you all, problem solved