Looping for checkbox in form

[sungpeng]

if($x==""){

$x=1;

}

while($do=mysql_fetch_array($sql){

<form name='Form' action='posting.php' method='post'>

<input type='checkbox' name='<?php print $x; ?>' value='<?php print $do[id]; ?>' />

<input type='submit' name='checked' value='checking'>

$x++;

}

 

 

When I click on the submit button, only one value of $x is sent to posting.php instead of multiple loop values in checkbox. Does anyone have a solution to it ?

 

Under Posting.php

for ($x = 1; $x <= 20; $x++) {

$x=$_POST[$x];

echo "$x";

}

Edited October 17, 2014 by sungpeng

[sungpeng]

if($x==""){

$x=1;

}

<form name='Form' action='posting.php' method='post'>

while($do=mysql_fetch_array($sql){

<input type='checkbox' name='<?php print $x; ?>' value='<?php print $do[id]; ?>' />

$x++;

}

<input type='submit' name='checked' value='checking'>

 

 Still the same problem

[QuickOldCar]

Only put in the loop the parts of form need to add new values with php

 

well you did not break out of php and back in, might as well echo in php

<form name='Form' action='posting.php' method='post'>
<?php
if($x==""){

$x=1;

}

while($do=mysql_fetch_array($sql){
echo "<input type='checkbox' name='".$x."' value='".$do[id]."' />";
$x++;
}
?>
<input type='submit' name='checked' value='checking'>
                 

Edited October 17, 2014 by QuickOldCar

[sungpeng]

No can't work. The posting.php display a word Array. Is there any edition to do with the posting.php page ? 

[sungpeng]

print_r(array_values($array)); 

still display only one value instead of many loop value.

[QuickOldCar]

Maybe this will help, i used a dummy range versus your while loop

<form name='Form' method='post'>
<?php
$dummy_array = range(1, 20);


$x = 1;

foreach ($dummy_array as $ids) {
    echo $x . ": <input type='checkbox' name='" . $x . "' value='" . $ids . "' /><br />";
    $x++;
}
?>
<input type='submit' name='checked' value='checking'><br />


<?php
//display
if (isset($_POST)) {
    foreach ($_POST as $key => $value) {
        echo $key . " - " . $value . "<br />";
    }
}
?>

[sungpeng]

I need the while loop to fetch data from mysql. If i use a while loop and put a foreach loop inside, it will generate a lot of unnecessary checkbox.

[sungpeng]

Another question is when i post it over to posting.php, can i just get the staff that is posted. No need to loop through all value to check if it contain value.

[sungpeng]

foreach ($_POST as $key => $value) {

echo "$key";

echo "$value";

}

 

 

$key and $value are empty.

[QuickOldCar]

The while loop is the loop.

 

and correct, just display the value in the $_POST array

 

instead of making each checkbox name a number, you can just make them an array and loop those

<form name='Form' method='post'>
<?php
$dummy_array = range(1,20);

foreach($dummy_array as $ids){
echo $ids.": <input type='checkbox' name='staff[]' value='".$ids."' /><br />";
}
?>
<input type='submit' name='checked' value='submit'><br />
<?php
//display
if(isset($_POST['staff'])){
foreach($_POST['staff'] as $staff){
echo $staff."<br />";
}
}
?>

Edited October 17, 2014 by QuickOldCar

[QuickOldCar]

So now I will put this together as what your code is, be sure to break in and out of php to html properly or echo the entire form in php

 

code:

<?php

echo "<form name='Form' action='posting.php' method='post'>";


while($do=mysql_fetch_array($sql){

echo $do['id'].": <input type='checkbox' name='staff[]' value='".$do['id']."' /><br />";

}

echo "<input type='submit' name='checked' value=checking'><br />";

?>

posting.php

<?php
//display on posting.php
if(isset($_POST['staff'])){
foreach($_POST['staff'] as $staff){
echo $staff."<br />";
}
}
?>

[sungpeng]

understood, it will get the value of the checked box. Wish to know how to get the value for the unchecked box ?

[sungpeng]

Sometime we got to check it and sometime uncheck it and update the uncheck in mysql as well.

[QuickOldCar]

Do you have a checked/unchecked value or equivalent in your database?

This way can mark the checked ones.

 

Taking a stab in the dark here...

if($do['checked'] == true){
$checked = "checked='checked'";
}else{
$checked = "";
}
echo "<input type='checkbox' name='staff[]' value='".$do['id']."' ".$checked." />";

If you want to pass all the staff regardless to checked or not can send a hidden value.

echo "<input type='hidden' name='allstaff[]' value='".$do['id']."' />";

so on display would be $_POST['allstaff']

Edited October 17, 2014 by QuickOldCar

[sungpeng]

Thank You