array() construct

[wdseelig]

I am looking at the following code snippet:

 

               functioncall(array(),$variable)

 

I've looked everywhere, but cannot find what this is supposed to mean.

 

In the function that is called I see

 

            function functioncall($var = array(), $var1 = array())

 

Is this some kind of cast??

 

Thanks!

[WinstonLA]

I don't understand what problem? Did you never see default parameters for functions?

[wdseelig]

of course I've seen default parameters, but that is not what the call to the function looks like [there is no = sign].  Does the (array(),$variable) construct mean that the function is being called with an array with a default value of $variable?

[wdseelig]

Or does it mean that functioncall is being called with two variables, the first of type array() and the second with value $variable?

[Barand]

 functioncall(array(),$variable)

 

is calling the function and passing two parameters. The first is an empty array, the second is whatever is in $variable. No different from

$a = array();
$b = array(1,2,3);
functioncall ($a, $b);

[wdseelig]

Thank you guru!!