foreach to create dropdown list problem

[ruraldev]

I have the following code which works (thanks to PHP Freaks members)

    foreach ($swap["sims"] as $swap) 
    		{
                    echo $swap['voice'] . "</br>";
			}

But I can't figure out why the following doesn't work

<select name="sim_for_swap[]">
<?php
    foreach ($swap["sims"] as $swap)  
    		{
?>
<option value="<?php echo $swap['voice'];?>"><?php echo $swap['voice'];?></option>
<?php
}
?>

[CroNiX]

It looks like it should work, if your first example works. What's not working about it? Do you close the </select> tag after the options are created in the loop?

[WinstonLA]

Change name for second variable in the foreach

foreach ($swap["sims"] as $swap)

foreach ($swap["sims"] as $swap)

 

 

This formatting looks better

<select name="sim_for_swap[]">
    <?php foreach ($swap["sims"] as $item): ?>
        <option value="<?php echo $item['voice']; ?>">
            <?php echo $item['voice']; ?>
        </option>
    <?php endforeach; ?>
</select>

Edited December 10, 2014 by WinstonLA

[ruraldev]

The nest line was closing the </select>

 

I tried the new format but still nothing appears in the dropdown list?

 

Weird?

[WinstonLA]

Hm...

Try this code

foreach ($swap["sims"] as $item) {
   var_dump($item);
}

Something is outputting on the screen?

If so, go back to your code and open (Ctrl+U) code of you page and find there your select tag. Will there be any options?

Edited December 10, 2014 by WinstonLA

[ruraldev]

I got it, turned out I was changing the value of a variable earlier in the code as I was outputting the variable for testing

 

Simple but rather silly mistake!