budimir Posted December 15, 2014 Share Posted December 15, 2014 (edited) Guys, How can I compare two values in same table. servis.kalkulacija_stavke ( id BIGINT(255) NOT NULL AUTO_INCREMENT, id_kalkulacija INT(255) NOT NULL, id_cjenika INT(255) NOT NULL, vrijeme TIMESTAMP DEFAULT CURRENT_TIMESTAMP, kataloski_broj VARCHAR(15) CHARACTER SET latin1 COLLATE latin1_swedish_ci NOT NULL, kategorija_artikla VARCHAR(10) CHARACTER SET latin1 COLLATE latin1_swedish_ci NOT NULL, grupa_proizvoda VARCHAR(10) CHARACTER SET latin1 COLLATE latin1_swedish_ci NOT NULL, podgrupa_proizvoda VARCHAR(15) CHARACTER SET latin1 COLLATE latin1_swedish_ci NOT NULL, cijena_EUR DECIMAL(20, 6) NOT NULL, cijena_KN DECIMAL(20, 6) NOT NULL, carina DECIMAL(20, 6) NOT NULL, spediter DECIMAL(20, 6) NOT NULL, banka DECIMAL(20, 6) NOT NULL, transport DECIMAL(20, 6) NOT NULL, nabavna_cijena DECIMAL(20, 6) NOT NULL, drezga_marza_po_grupi DECIMAL(20, 6) NOT NULL, drezga_zarada DECIMAL(20, 6) NOT NULL, neto_VPC DECIMAL(20, 6) NOT NULL, neto_MPC DECIMAL(20, 6) NOT NULL, trosak_firme DECIMAL(20, 6) NOT NULL, trosak_firme_p DECIMAL(20, 6) NOT NULL, diler_marza_po_grupi DECIMAL(20, 6) NOT NULL, preporucena_VPC DECIMAL(20, 6) NOT NULL, preporucena_MPC DECIMAL(20, 6) NOT NULL, zarada_diler_kn DECIMAL(20, 6) NOT NULL, zarada_diler_post DECIMAL(20, 6) NOT NULL, zarada_za_nas_kn DECIMAL(20, 6) NOT NULL, zarada_za_nas_post DECIMAL(20, 6) NOT NULL, brutto_zarada_za_nas_kn DECIMAL(20, 6) NOT NULL, brutto_zarada_za_nas_post DECIMAL(20, 6) NOT NULL, godina YEAR(4) NOT NULL, PRIMARY KEY (id), INDEX id (id), INDEX kat_br (kataloski_broj), INDEX kataloski_broj (kataloski_broj, kategorija_artikla, grupa_proizvoda, podgrupa_proizvoda) ) ENGINE = MYISAM AUTO_INCREMENT = 1119990 AVG_ROW_LENGTH = 264 CHARACTER SET utf8 COLLATE utf8_general_ci; I want to compare field nabavna_cijena in last year and this year. How can I achieve that? Edited December 15, 2014 by budimir Quote Link to comment https://forums.phpfreaks.com/topic/293106-compare-two-values-in-same-table/ Share on other sites More sharing options...
Barand Posted December 15, 2014 Share Posted December 15, 2014 Do you mean SELECT YEAR(vrijeme), SUM(nabavna_cijena) as total FROM kalkulacija_stavke WHERE YEAR(vrijeme) > YEAR(CURDATE()) -2 GROUP BY YEAR(vrijeme) Quote Link to comment https://forums.phpfreaks.com/topic/293106-compare-two-values-in-same-table/#findComment-1499623 Share on other sites More sharing options...
budimir Posted December 15, 2014 Author Share Posted December 15, 2014 Do you mean SELECT YEAR(vrijeme), SUM(nabavna_cijena) as total FROM kalkulacija_stavke WHERE YEAR(vrijeme) > YEAR(CURDATE()) -2 GROUP BY YEAR(vrijeme) Barand, thanks for you're answer, but I would need something like: If nabavna_cijena (last year) < nabavna_cijena (this year) as less If nabavna_cijena (last year) > nabavna_cijena (this year) as more Quote Link to comment https://forums.phpfreaks.com/topic/293106-compare-two-values-in-same-table/#findComment-1499624 Share on other sites More sharing options...
Solution Barand Posted December 15, 2014 Solution Share Posted December 15, 2014 How about SELECT a.yr , a.tot as yr_tot , b.tot as prev_yr_tot , IF(a.tot>=b.tot, 'more','') as more , IF(a.tot< b.tot, 'less','') as less FROM ( SELECT YEAR(vrijeme) as yr , SUM(nabavna_cijena) as tot FROM kalkulacija_stavke GROUP BY YEAR(vrijeme) ) as a LEFT JOIN ( SELECT YEAR(vrijeme) as yr , SUM(nabavna_cijena) as tot FROM kalkulacija_stavke GROUP BY YEAR(vrijeme) ) as b ON a.yr = b.yr + 1; 1 Quote Link to comment https://forums.phpfreaks.com/topic/293106-compare-two-values-in-same-table/#findComment-1499625 Share on other sites More sharing options...
budimir Posted December 15, 2014 Author Share Posted December 15, 2014 How about SELECT a.yr , a.tot as yr_tot , b.tot as prev_yr_tot , IF(a.tot>=b.tot, 'more','') as more , IF(a.tot< b.tot, 'less','') as less FROM ( SELECT YEAR(vrijeme) as yr , SUM(nabavna_cijena) as tot FROM kalkulacija_stavke GROUP BY YEAR(vrijeme) ) as a LEFT JOIN ( SELECT YEAR(vrijeme) as yr , SUM(nabavna_cijena) as tot FROM kalkulacija_stavke GROUP BY YEAR(vrijeme) ) as b ON a.yr = b.yr + 1; Thanks Barand! Quote Link to comment https://forums.phpfreaks.com/topic/293106-compare-two-values-in-same-table/#findComment-1499631 Share on other sites More sharing options...
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