tjhilder Posted November 24, 2005 Share Posted November 24, 2005 Hi, I want to delete multiple records via a form, but I'm not sure how I should go about this. if someone could show me how I would edit this code: while ($row = mysql_fetch_array ($r)) { echo "\n<tr>\n<td class=\"commentid-number\">{$row['id']}</td>\n<td class=\"commentid-user\">{$row['user']}</td><td class=\"commentid-date\">{$row['date']}</td>\n<td class=\"commentid-edit\"><a href=\"$url?show=edit&id={$row['id']}\">click</a></td>\n<td class=\"commentid-delete\"><a href=\"$url?show=delete&id={$row['id']}\">click</a></td>\n</tr>"; } so that instead of <a href=\"$url?show=delete&id={$row['id']}\">click</a> it would be <input type="checkbox" name="id" value="{$row['id']}"> I think that part is right (if not, please tell me), but I don't know how I would go about it with the query. can someone help me with this? thanks in advanced. -- TJ Quote Link to comment Share on other sites More sharing options...
tjhilder Posted November 26, 2005 Author Share Posted November 26, 2005 anyone able to help? Quote Link to comment Share on other sites More sharing options...
ryanlwh Posted November 26, 2005 Share Posted November 26, 2005 name the checkboxes like this <input type="checkbox" name="id[]" value="{$row['id']}"> this would produce echo $_POST['id'][0]; //first id echo $_POST['id'][1]; //second id etc Quote Link to comment Share on other sites More sharing options...
tjhilder Posted November 27, 2005 Author Share Posted November 27, 2005 ah, thanks for reply. does that mean that if I use this mysql query: $query = "DELETE FROM news WHERE news_id={$_POST['id']} that it will delete all the id's or is there more code needed? Edit: I thought I'd try it, but it didn't work (as I expected) got this error: Unknown column 'Array' in 'where clause'. The query was DELETE FROM news WHERE news_id=Array. Quote Link to comment Share on other sites More sharing options...
ryanlwh Posted November 27, 2005 Share Posted November 27, 2005 you need to loop through the array foreach ($_POST['id'] as $v) { $query = "DELETE FROM news WHERE news_id='$v'"; mysql_query($query); } Quote Link to comment Share on other sites More sharing options...
tjhilder Posted November 29, 2005 Author Share Posted November 29, 2005 I have my code like this now, but it turned up an error. if (isset ($_POST['submit'])) { // Handle the form. // Define the query. foreach ($_POST['id'] as $v) { $query = "DELETE FROM news WHERE news_id='$v'"; $r = mysql_query ($query); // Execute the query. } // Report on the result. if (mysql_affected_rows() == 1) { echo "\t\t\t\t\t<div class=\"news-box\">\n\t\t\t\t\t\t<div class=\"news-title\">\n\t\t\t\t\t\t\t:: Success\n\t\t\t\t\t\t</div>\n\t\t\t\t\t\t<div class=\"news-article\">\n\t\t\t\t\t\t\tThe Article has been deleted.<br /><br /><a href=\"$url?show=list\">Back</a>\n\t\t\t\t\t\t</div>\n\t\t\t\t\t</div>\n"; } else { echo "\t\t\t\t\t<div class=\"news-box\">\n\t\t\t\t\t\t<div class=\"news-title\">\n\t\t\t\t\t\t\t:: Error\n\t\t\t\t\t\t</div>\n\t\t\t\t\t\t<div class=\"news-article\">\n\t\t\t\t\t\t\tMySQL Error Information: <b>" . mysql_error() . "</b>. The query was $query.\n\t\t\t\t\t\t</div>\n\t\t\t\t\t</div>\n"; } } MySQL Error Information: . The query was DELETE FROM news WHERE news_id=''. I have the code like this in another part of my code: <input type="checkbox" name="id[]" value="{$row['id']}"> Quote Link to comment Share on other sites More sharing options...
ryanlwh Posted November 29, 2005 Share Posted November 29, 2005 you should put that if/else clause inside the loop. Quote Link to comment Share on other sites More sharing options...
tjhilder Posted November 30, 2005 Author Share Posted November 30, 2005 Ok I did as you said: // Define the query. foreach ($_POST['id'] as $v) { $query = "DELETE FROM news WHERE news_id='$v'"; $r = mysql_query ($query); // Execute the query. // Report on the result. if (mysql_affected_rows() >= 1) { echo "\t\t\t\t\t<div class=\"news-box\">\n\t\t\t\t\t\t<div class=\"news-title\">\n\t\t\t\t\t\t\t:: Success\n\t\t\t\t\t\t</div>\n\t\t\t\t\t\t<div class=\"news-article\">\n\t\t\t\t\t\t\tThe Article has been deleted.<br /><br /><a href=\"$url?show=list\">Back</a>\n\t\t\t\t\t\t</div>\n\t\t\t\t\t</div>\n"; } else { echo "\t\t\t\t\t<div class=\"news-box\">\n\t\t\t\t\t\t<div class=\"news-title\">\n\t\t\t\t\t\t\t:: Error\n\t\t\t\t\t\t</div>\n\t\t\t\t\t\t<div class=\"news-article\">\n\t\t\t\t\t\t\tMySQL Error Information: <b>" . mysql_error() . "</b>. The query was $query.\n\t\t\t\t\t\t</div>\n\t\t\t\t\t</div>\n"; } } now I get 2 error messages (probably cos I was trying to delete 2 things at once): MySQL Error Information: . The query was DELETE FROM news WHERE news_id=''. Quote Link to comment Share on other sites More sharing options...
ryanlwh Posted November 30, 2005 Share Posted November 30, 2005 it's weird that mysql_error() was empty. View source on the form page, see if the checkboxes have values, and make sure you don't have something named id elsewhere. Quote Link to comment Share on other sites More sharing options...
tjhilder Posted December 1, 2005 Author Share Posted December 1, 2005 Ah! it's working now! thanks for your help. I found that it was trying to get 'id' from the mysql table but it's not id, it's news_id so I changed that, I also changed the foreach () with id to article_id (just in case it mixed with something else) wasn't and id[] to article_id[] for same reason. although one thing I do want to fix now is the multiple messages that I get, because the mysql_affected_rows() is in the foreach, is there a way around this? EDIT: I do believe that I might have solved it, although if you have a better idea then mine i'd like it -------------- changed echo "error"; or echo "success"; for $information = "error"; or $information = "success"; -------------- then did an echo $information; outside the foreach statement (so if nothing there it just remains blank.) Quote Link to comment Share on other sites More sharing options...
ryanlwh Posted December 2, 2005 Share Posted December 2, 2005 or you could put those success/error messages into an array (or concatenate into a string), and print the array or string after the loop. There really is no "best" way. Quote Link to comment Share on other sites More sharing options...
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