PHPBear Posted January 12, 2015 Share Posted January 12, 2015 I got some code to make a simple quiz, but I'm struggling to get it to work. I think the form and the following JavaScript code are set up correctly, but I'm running into problems with the PHP code at the end. I'm especially confused by the JSON reference at the very end; I don't have a clue what it means or what do do with it. Does anyone know how to fix/complete this script? On another note, why is it necessary to use JSON in the first place? Aren't the answers already provided in the PHP code (e.g. $answer1 = $_POST['A']? Thanks. <form action=""> <fieldset> What color is an apple? <label>blue <input type="radio" value="A" name="question-1"></label> <label>red <input type="radio" value="B" name="question-1"></label> <label>yellow <input type="radio" value="C" name="question-1"></label> <label>gray <input type="radio" value="D" name="question-1"></label> </fieldset> <fieldset> What color is a banana? <label>yellow <input type="radio" value="A" name="question-2"></label> <label>blue <input type="radio" value="B" name="question-2"></label> <label>red <input type="radio" value="C" name="question-2"></label> <label>gray <input type="radio" value="D" name="question-2"></label> </fieldset> <fieldset> What color is the sky? <label>yellow <input type="radio" value="A" name="question-3"></label> <label>blue <input type="radio" value="B" name="question-3"></label> <label>red <input type="radio" value="C" name="question-3"></label> <label>gray <input type="radio" value="D" name="question-3"></label> </fieldset> <fieldset> What color is snow? <label>white <input type="radio" value="A" name="question-4"></label> <label>blue <input type="radio" value="B" name="question-4"></label> <label>red <input type="radio" value="C" name="question-4"></label> <label>gray <input type="radio" value="D" name="question-4"></label> </fieldset> <input type="button" value="Submit" class="submit" id="Submit2"> </form> <script> $(function(){ // Trap the form submit event $('form').submit(function(e){ e.preventDefault() // Prevent browser refresh var answers = $(this).seralize() // Manually send the data with AJAX $.post({ url: $(this).attr('action'), data: answers, // Stuff to do after we get a response success: function(response){ $('#results').text(response.correct) } }) }) }) </script> <?php $answer1 = $_POST['A']; $answer2 = $_POST['A']; $answer3 = $_POST['C']; $answer4 = $_POST['D']; $totalCorrect = 0; if ($answer1 == "B") { $totalCorrect++; } if ($answer2 == "A") { $totalCorrect++; } if ($answer3 == "B") { $totalCorrect++; } if ($answer4) { $totalCorrect++; } // Send the data back as JSON die json_encode(array( 'correct' => $totalCorrect; )); ?> Quote Link to comment Share on other sites More sharing options...
Solution mac_gyver Posted January 12, 2015 Solution Share Posted January 12, 2015 the php json code is sending the 'correct' => $totalCorrect;response back to the browser, that the ajax code is using to display how many answers are correct via this - $('#results').text(response.correct) the most immediate problem why your code isn't working is because your form field name = '...' attributes are question-1, question-2, question-3, ... you would need to use those same names in the $_POST[...] variables to access the values. another problem is because you are submitting the ajax request to the (apparently) same page as your main page, all the output, including the form's html, is being sent back to the browser in the ajax response. you would need to have conditional logic so that when it receives the post request, that the only output it sends is the json_encode() output. Quote Link to comment Share on other sites More sharing options...
PHPBear Posted January 12, 2015 Author Share Posted January 12, 2015 Thanks. Quote Link to comment Share on other sites More sharing options...
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