Saber Posted February 21, 2015 Share Posted February 21, 2015 Hi, Please check the code below, I am able to insert the records in the database through CSV file but unable to update. No error is generating but not updating <?php //Upload File if (isset($_POST['submit'])) { if (is_uploaded_file($_FILES['filename']['tmp_name'])) { echo "<h1>" . "File ". $_FILES['filename']['name'] ." uploaded successfully." . "</h1>"; echo "<h2>Displaying contents:</h2>"; readfile($_FILES['filename']['tmp_name']); } //Import uploaded file to Database $handle = fopen($_FILES['filename']['tmp_name'], "r"); while (($data = fgetcsv($handle, 2000, ",")) !== FALSE){ $Sql=mysql_query("select * from test where id ='$id'"); if(mysql_num_rows($Sql) > 0) { $import="update test set `name`='$data[1]', `gender`='$data[2]', `designation`='$data[3]' where id='$data[0]'"; mysql_query($import) or die(mysql_error()); } else { $import="insert into test set `name`='$data[1]', `gender`='$data[2]', `designation`='$data[3]', `id`='$data[0]'"; mysql_query($import) or die(mysql_error()); } } fclose($handle); print "Update done"; Quote Link to comment Share on other sites More sharing options...
marius_haugan Posted February 21, 2015 Share Posted February 21, 2015 See how much easier your code is to read now? if (isset($_POST['submit'])) { if (is_uploaded_file($_FILES['filename']['tmp_name'])) { echo "<h1>" . "File ". $_FILES['filename']['name'] ." uploaded successfully." . "</h1>"; echo "<h2>Displaying contents:</h2>"; readfile($_FILES['filename']['tmp_name']); } //Import uploaded file to Database $handle = fopen($_FILES['filename']['tmp_name'], "r"); while (($data = fgetcsv($handle, 2000, ",")) !== FALSE){ $Sql=mysql_query("select * from test where id ='$id'"); if(mysql_num_rows($Sql) > 0) { $import="update test set `name`='$data[1]', `gender`='$data[2]', `designation`='$data[3]' where id='$data[0]'"; mysql_query($import) or die(mysql_error()); } else { $import="insert into test set `name`='$data[1]', `gender`='$data[2]', `designation`='$data[3]', `id`='$data[0]'"; mysql_query($import) or die(mysql_error()); } } fclose($handle); print "Update done"; Quote Link to comment Share on other sites More sharing options...
Saber Posted February 21, 2015 Author Share Posted February 21, 2015 @ marius May I know the error???????????? Quote Link to comment Share on other sites More sharing options...
Saber Posted February 21, 2015 Author Share Posted February 21, 2015 nobody here to help me out/???????? Quote Link to comment Share on other sites More sharing options...
mac_gyver Posted February 21, 2015 Share Posted February 21, 2015 $Sql=mysql_query("select * from test where id ='$id'"); ^^^ in the above line in your code, there is no $id variable in your code, so that query is never finding anything, so the update branch logic never runs. if you had php's error_reporting set to E_ALL and display_errors set to ON, php would be outputting an undefined variable error to alert you to the problem with the $id variable. you don't need to select the data in order to find out if you should insert or update something, mysql has an INSERT ... ON DUPLICATE KEY UPDATE query - http://dev.mysql.com/doc/refman/5.6/en/insert-on-duplicate.html you can also use a LOAD DATA LOCAL INFILE query to import the data from a file. Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.