brian429 Posted April 26, 2015 Share Posted April 26, 2015 <?php $id = $_GET['keyword']; echo $id;?> Using my site as http://my site/?keyword=32 - this is just a example would actually be http://my site/?keyword={age:30-50} and the platform I am advertising on passes the age that way. I am curious is there a way to use If for example if $id > 29 or <34 $age = 30 - 34 if $id > 29 or <39 $age = 35 - 39 and so on so it looks more targeted to the user, I feel the above code would look to fake if it called out there exact age. Thanks in advance Link to comment https://forums.phpfreaks.com/topic/295874-how-would-i-do-this-while-passing-keywords/ Share on other sites More sharing options...
nik_jain Posted April 26, 2015 Share Posted April 26, 2015 I don't think I understand what you require, but the string {age:30-50} is a json encoded string . You can get the value by $string = '{age:30-50}' ; $age_obj= json_decode($string) ; $age = $age_obj->age ; Something like that Link to comment https://forums.phpfreaks.com/topic/295874-how-would-i-do-this-while-passing-keywords/#findComment-1509982 Share on other sites More sharing options...
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