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Hello,

 

I am new to php and stuck on this msqli function.

 

I would like to echo out all the results divided by commas and apostrophe.  Example:  "23232","324231","342533"

 

With the last one not having a comma.

 

Here is what I came up with and not sure why I am getting errors.

 

I think this is the issue but not sure: $list.= $result->'"'.video_code.'",';

 

 

Thanks.

$sql = 'SELECT video_code FROM yt_videos WHERE yt_video_item_id="'.$vidid.'" ORDER BY RAND() LIMIT 10'; 
			
$query = mysqli_query($db_conx, $sql);
			
			
$list='';
while ($result = $query ->fetch_object()) {
$list.= $result->'"'.video_code.'",';
}
					
echo $list=substr($list,0,-1); 

Thanks for the reply. I don't quite understand how to implement the join function in my code.

 

I think I am close other wise as I am no longer getting an error but not quite the result I need.

 

When I use this code it works:

$list.= $result->video_code.'",';

Resulting in 2343234",345353",43533534"

 

How do I write that line to include a " before each row result too.  Looking for "2343234","345353","43533534" 

 

Thanks.

Ok I tried the join function but now I am getting an error: Warning: join() [function.join]: Invalid arguments passed in...

 

Here is my code.  I just don't understand mysqli, I just have some experience and mysql.

$sql='SELECT video_code FROM yt_videos WHERE yt_video_item_id="'.$vidid.'" ORDER BY RAND() LIMIT 10';
$result=mysqli_query($db_conx,$sql);
			
mysqli_free_result($result);
echo '"' . join('","', $result) . '"';
Edited by solidrocketfuel

Thanks Fastol.  That helped.  Now its only echoing one result.

 

Here is my code now.  No errors!! Getting close! :)

 

$sql = 'SELECT video_code FROM yt_videos WHERE yt_video_item_id="'.$vidid.'" ORDER BY RAND() LIMIT 10';


$result=mysqli_query($db_conx,$sql);


// Associative array
$row = mysqli_fetch_assoc($result);
  
   echo '"' . join('","', $row) . '"';

Sorry for being such a newbie guys.  Just fixed the single echo with a while loop. But the only problem is that the comma between echos is not work.

 

My result is:  "_IvF4X658hY""DRF6b1N_KFk""G-keFAKQHy4"              

 

My code: 

 

$sql = 'SELECT video_code FROM yt_videos WHERE yt_video_item_id="'.$vidid.'" ORDER BY RAND() LIMIT 10';


$result=mysqli_query($db_conx,$sql);


// Associative array
while ( $row = mysqli_fetch_assoc($result)) 
  
   echo '"' . join('","', $row) . '"'  

The code works for me when I test it like this, basically simulating an array.

$a = array(
	"_IvF4X658hY",
	"DRF6b1N_KFk",
	"G-keFAKQHy4"
);

 echo '"' . join('","', $a) . '"'

The problem is likely that $row is not what you want to give the join(), meaning it's probably not formatted right.  Do a print_r($row); in the while() and post it back here so I can see what the array looks like.

I was curious why you are trying to echo them wrapped double quotes and commas

 

 

Make it an array in the loop

$sql = 'SELECT video_code FROM yt_videos WHERE yt_video_item_id="'.$vidid.'" ORDER BY RAND() LIMIT 10';

$result=mysqli_query($db_conx,$sql);
$video_codes = array();
// Associative array
while ( $row = mysqli_fetch_assoc($result)){
    $video_codes[] = $row['video_code'];
    echo $row['video_code']."<br />";
}

if(!empty($video_codes)){
print_r($video_codes);
echo '"' . join('","', $video_codes) . '"';
}


Store the things you want to join in the array

$sql = 'SELECT video_code FROM yt_videos WHERE yt_video_item_id="'.$vidid.'" ORDER BY RAND() LIMIT 10';

$result=mysqli_query($db_conx,$sql);

$codes = array();

while ($row = mysqli_fetch_assoc($result)) {
    $codes[] = $row['video_code'];  // add code to the array
}   

// now join the array of codes
echo '"' . join('","', $codes) . '"';

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