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I am using a drop-down box to fetch the result from MySQL and once i select the result from drop-down it will populate my html text-boxes. it was working fine until i added another drop-down. Kindly have a look at the link and let me know. I am new in programming. let me know if you need anymore elaboration. Thank you
http://pastebin.com/EJKA9RsK
This part is working

//This part is working
<?php
$vbCrLf = chr(13).chr(10);
error_reporting(0);
// open connection to MySQL server
$link = mysqli_connect("localhost", "root", "root", "print")
or die ('Unable to connect!');


//create and execute query
$query = "SELECT bin, iban, bename, benadd, bcoun, bcode, bname, badd FROM datee";
$result = mysqli_query($link,$query); 

//create selection list
$DropDownList .= "<select name='Company' id='DropDownListId' onchange='javascript:SelectChanged();'> ".$vbCrLf;
$DropDownList .= "<option value=''></option> ".$vbCrLf;

while($row = mysqli_fetch_row($result))
{
$heading = $row[0];
$DropDownList .= "<option value='$heading'>$heading</option> ".$vbCrLf;


$IbnArrayPhp .= 'IbnArray["'.$heading.'"]="'.$row[1].'";'.$vbCrLf;
$BenameArrayPhp .= 'BenameArray["'.$heading.'"]="'.$row[2].'";'.$vbCrLf;
$BenaddArrayPhp .= 'BenaddArray["'.$heading.'"]="'.$row[3].'";'.$vbCrLf;
$BcounArrayPhp .= 'BcounArray["'.$heading.'"]="'.$row[4].'";'.$vbCrLf;
$BcodeArrayPhp .= 'BcodeArray["'.$heading.'"]="'.$row[5].'";'.$vbCrLf;
$BnameArrayPhp .= 'BnameArray["'.$heading.'"]="'.$row[6].'";'.$vbCrLf;
$BaddArrayPhp .= 'BaddArray["'.$heading.'"]="'.$row[7].'";'.$vbCrLf;
}
$DropDownList .= "</select> ".$vbCrLf;
?>


<script language="Javascript" type="text/javascript">
var IbnArray = new Array();
<?php echo $IbnArrayPhp; ?>
var BenameArray = new Array();
<?php echo $BenameArrayPhp; ?>
var BenaddArray = new Array();
<?php echo $BenaddArrayPhp; ?>
var BcounArray = new Array();
<?php echo $BcounArrayPhp; ?>
var BcodeArray = new Array();
<?php echo $BcodeArrayPhp; ?>
var BnameArray = new Array();
<?php echo $BnameArrayPhp; ?>
var BaddArray = new Array();
<?php echo $BaddArrayPhp; ?>
function SelectChanged()
{
var Company = document.getElementById('DropDownListId').value;
document.getElementById('iban').value = IbnArray[Company];
document.getElementById('bename').value = BenameArray[Company];
document.getElementById('benadd').value = BenaddArray[Company];
document.getElementById('bcoun').value = BcounArray[Company];
document.getElementById('bcode').value = BcodeArray[Company];
document.getElementById('bname').value = BnameArray[Company];
document.getElementById('badd').value = BaddArray[Company];

}
</script>
<?php echo $DropDownList; ?>
</label>
</legend>

This part is not working
 

//This part is not working
<?php
$vbCrLf1 = chr(13).chr(10);
error_reporting(0);
// open connection to MySQL server
$link1 = mysqli_connect("localhost", "root", "root", "print")
or die ('Unable to connect!');


//create and execute query
$query1 = "SELECT aini, acname, acnum, num2, num3 FROM datee";
$result1 = mysqli_query($link1,$query1); 

//create selection list
$DropDownList1 .= "<select name='Company1' id='DropDownList1Id' onchange='javascript:SelectChanged();'> ".$vbCrLf1;
$DropDownList1 .= "<option value=''></option> ".$vbCrLf1;

while($row1 = mysqli_fetch_row($result1))
{
$heading1 = $row1[0];
$DropDownList1 .= "<option value='$heading1'>$heading1</option> ".$vbCrLf1;


$AcnameArrayPhp .= 'AcnameArray["'.$heading1.'"]="'.$row1[1].'";'.$vbCrLf1;
$AcnumArrayPhp .= 'AcnumArray["'.$heading1.'"]="'.$row1[2].'";'.$vbCrLf1;
$Num2ArrayPhp .= 'Num2Array["'.$heading1.'"]="'.$row1[3].'";'.$vbCrLf1;
$Num3ArrayPhp .= 'Num3Array["'.$heading1.'"]="'.$row1[4].'";'.$vbCrLf1;

}
$DropDownList1 .= "</select> ".$vbCrLf1;
?>


<script language="Javascript" type="text/javascript">
var AcnameArray = new Array();
<?php echo $AcnameArrayPhp; ?>
var AcnumArray = new Array();
<?php echo $AcnumArrayPhp; ?>
var Num2Array = new Array();
<?php echo $Num2ArrayPhp; ?>
var Num3Array = new Array();
<?php echo $Num3ArrayPhp; ?>


function SelectChanged()
{
var Company1 = document.getElementById('DropDownList1Id').value;
document.getElementById('acname').value = AcnameArray[Company1];
document.getElementById('acnum').value = AcnumArray[Company1];
document.getElementById('num2').value = Num2Array[Company1];
document.getElementById('num3').value = Num3Array[Company1];



}
</script>
<?php echo $DropDownList1; ?>
</label>
</legend>
Link to comment
https://forums.phpfreaks.com/topic/296880-mysql-php-dropdown-not-showing-anything/
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