Function "UPDATE db..." getting the wrong $ID

GustavoLopesC · June 28, 2015

Hello ,

I have one page that makes a search inside the DB MYSQL about whats was wrote in the search field.

And returns me a registry.

In this same page i have one field and a button that change one data of this registry. For make this work in the registry found in the search , i used the $id like reference. But it's going to the wrong $id in the DB (only change the first id on the table) , instead of change the registry that i found. What's wrong ?

Code:

<?php
include "config.php";
?>

<?php
mysql_set_charset('utf8');
ini_set('default_charset','UTF-8');
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Resultado Busca</title>
</head>

<body>

<a href="/admin/painel/buscar.php">
<img src="/img/back.png" /></a
><br/>
<br/>
<br/>

<?php
$buscar=$_POST['buscar'];
$sql = mysql_query("SELECT * FROM trocasrecebidas WHERE correios LIKE '%".$buscar."%'");
$row = mysql_num_rows($sql);
if ($row > 0) {
	while($linha = mysql_fetch_array($sql)) {
$id = $linha['id'];
$nome = $linha['nome'];
$email=$linha['email'];
$telefone=$linha['telefone'];
$pedido=$linha['pedido'];
$correios=$linha['correios'];
$endereco=$linha['endereco'];
$cep=$linha['cep'];
$cidade=$linha['cidade'];
$estado=$linha['estado'];
$motivodefeito=$linha['motivodefeito'];
$motivoerrado=$linha['motivoerrado'];
$motivodesistiu=$linha['motivodesistiu'];
echo "<strong>ID: </strong>".@$id;
echo "<br/><br/>";
echo "<strong>Nome: </strong>".@$nome;
echo "<br/><br/>";
echo "<strong>Email: </strong>".@$email;
echo "<br/><br/>";
echo "<strong>Telefone: </strong>".@$telefone;
echo "<br/><br/>";
echo "<br/><br/>";echo "<br/>";
echo "<strong>N°do pedido: </strong>".@$pedido;
echo "<br/><br/>";
echo "<strong>Cód. de rastreamento: </strong>".@$correios;
echo "<br/><br/>";
echo "<strong>Produto com defeito: </strong>".@$motivodefeito;
echo "<br/>";
echo "<strong>Produto errado: </strong>".@$motivoerrado;
echo "<br/>";
echo "<strong>Desistência: </strong>".@$motivodesistiu;
echo "<br/>";
echo "<br/><br/>";echo "<br/>";
echo "<strong>Endereço: </strong>".@$endereco;
echo "<br/><br/>";
echo "<strong>CEP: </strong>".@$cep;
echo "<br/><br/>";
echo "<strong>Cidade: </strong>".@$cidade;
echo "<br/><br/>";
echo "<strong>Estado: </strong>".@$estado;
echo "<br/><br/>";echo "<br/>";echo "<br/><br/>";
	}
} else {
	echo "Nenhum registro encontrado.";
}
?>
<p>
<p>
<p>
<p>
<form name="button" method="post" action="">
<input type="submit" value="Imprimir" />
</form>


<br/><br/>
<form name="searchform" method="post" action="?a=ok">
<input type="text" name="newrastreio" />  <input type="submit" value="Novo Rastreamento" />
</form>
<?php
if ( isset( $_GET['a'] ) && $_GET['a'] == 'ok'   ) {
$newrastreio=$_POST['newrastreio'];
$alterarDado = mysql_query("UPDATE trocasrecebidas SET newrastreio = '".$newrastreio."' WHERE id = '".@$id."'") or die (mysql_error());

}
?>
</body>
</html>

The part of the problem:

<form name="searchform" method="post" action="?a=ok">
<input type="text" name="newrastreio" />  <input type="submit" value="Novo Rastreamento" />
</form>
<?php
if ( isset( $_GET['a'] ) && $_GET['a'] == 'ok'   ) {
$newrastreio=$_POST['newrastreio'];
$alterarDado = mysql_query("UPDATE trocasrecebidas SET newrastreio = '".$newrastreio."' WHERE id = '".@$id."'") or die (mysql_error());

}
?>

Thanks

fastsol · June 29, 2015

$id will always only be the value of the last row the while loop gathers cause it's being reset with each loop of the while.

GustavoLopesC · June 29, 2015

$id will always only be the value of the last row the while loop gathers cause it's being reset with each loop of the while.

And what can i do ?

Ch0cu3r · June 30, 2015

You will need to output the form within the while loop and set the id as a hidden input field.

while($linha = mysql_fetch_array($sql))
{
    $id = $linha['id'];
    ....

    echo '<form name="searchform" method="post" action="?a=ok">
              <input type="text" name="newrastreio" />
              <input type="hidden" name="id" value="' . $id . '" />
              <input type="submit" value="Novo Rastreamento" />
          </form>';
}

When updating the record you get the id value from $_POST['id']

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Function "UPDATE db..." getting the wrong $ID

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