Get highest folder PHP

[Guest MrLeN]

I have a directory with folder numbers, ie:

 

1

2

3

4

 

..and I have created the ability to delete folders. So 2 could be deleted and I'll wind up with:

 

1

3

4

 

..that's all well and good, but before I added the ability to delete folders, I was simply counting the folders, adding 1 to what ever the count was, and then creating a new folder with the new number.

 

My Problem:

 

If I use that process, the next number will be 4 (which already exists).

 

So now what I have decided I'm going to have to do is get all the folder numbers, then get the highest folder number, and add one to THAT number.

 

 

if ($handle = opendir('.')) {

while (false !== ($entry = readdir($handle))) {

if ($entry != "." && $entry != "..") {

echo "$entry\n";
}
}

closedir($handle);
}

 

How can I get the highest number of $entry?

 

 

[scootstah]

Use glob() to get the directory names and then use max() to get the highest one.

[Guest MrLeN]

How do I turn glob() values into an array?

[scootstah]

It returns an array.

 

Return Values

 

Returns an array containing the matched files/directories, an empty array if no file matched or FALSE on error.

[Guest MrLeN]

Here is the solution I came up with:

 

 

$dir1 = $path . '/1';
$dir2 = $path . '/2';
$dir3 = $path . '/3';
$dir4 = $path . '/4';
$dir5 = $path . '/5';
$dir6 = $path . '/6';
$dir8 = $path . '/7';
$dir9 = $path . '/8';
$dir10 = $path . '/10';
$dir11 = $path . '/11';
$dir12 = $path . '/12';
$dir13 = $path . '/13';
$dir14 = $path . '/14';
$dir15 = $path . '/15';
$dir16 = $path . '/16';
$dir17 = $path . '/17';
$dir18 = $path . '/18';
$dir19 = $path . '/19';
$dir20 = $path . '/20';
 
if (!file_exists($dir1)) {
echo "creating dir 1";
}
else {
if (!file_exists($dir2)) {
echo "creating dir 2";
}
else {
if (!file_exists($dir3)) {
echo "creating dir 3";
}
else {
if (!file_exists($dir4)) {
echo "creating dir 4";
}
else {
if (!file_exists($dir5)) {
echo "creating dir 5";
}
else {
if (!file_exists($dir6)) {
echo "creating dir 6";
}
else {
if (!file_exists($dir7)) {
echo "creating dir 7";
}
else {
if (!file_exists($dir8)) {
echo "creating dir 8";
}
else {
if (!file_exists($dir9)) {
echo "creating dir 9";
}
else {
if (!file_exists($dir10)) {
echo "creating dir 10";
}
else {
if (!file_exists($dir11)) {
echo "creating dir 11";
}
else {
if (!file_exists($dir12)) {
echo "creating dir 12";
}
else {
if (!file_exists($dir13)) {
echo "creating dir 13";
}
else {
if (!file_exists($dir14)) {
echo "creating dir 14";
}
else {
if (!file_exists($dir15)) {
echo "creating dir 15";
}
else {
if (!file_exists($dir16)) {
echo "creating dir 16";
}
else {
if (!file_exists($dir17)) {
echo "creating dir 17";
}
else {
if (!file_exists($dir18)) {
echo "creating dir 18";
}
else {
if (!file_exists($dir19)) {
echo "creating dir 19";
}
else {
if (!file_exists($dir20)) {
echo "creating dir 20";
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}

[Ch0cu3r]

Why? Whats wrong with what scootstah told you to do.

[Guest MrLeN]

Why? Whats wrong with what scootstah told you to do.

 

I do not understand what he is saying in the slightest. Not a clue..

[scootstah]

Did you even bother to read the manual for the functions I gave you?

 

If you want to hard code it, at the very least do this so it's not a maintenance nightmare:

$max = 20;

for ($i = 1; $i <= $max; i++) {
    $dir = $path . '/' . $i;

    if (!file_exists($dir)) {
        echo 'Creating dir ' . $i;
        break;
    }
}

Edited September 8, 2015 by scootstah

[Guest MrLeN]

Did you even bother to read the manual for the functions I gave you?

 

If you want to hard code it, at the very least do this so it's not a maintenance nightmare:

$max = 20;

for ($i = 1; $i <= $max; i++) {
    $dir = $path . '/' . $i;

    if (!file_exists($dir)) {
        echo 'Creating dir ' . $i;
        break;
    }
}

I did look for about 5 minutes. It gave me a headache. Hence my question: "How do I turn glob() values into an array?" .. it wasn't long after that I started to feel nauseous.. so I decided to sit back, have a think -- and write up some code that I understand. I can see you're unimpressed, but my solution was to the best of my ability. I am not a very good programmer; but I try hard.

[Guest MrLeN]

Thanks for the short code though

 

I'll see if I can implement it.

[Guest MrLeN]

That code gave me an error.

 

 

Parse error: syntax error, unexpected T_INC, expecting ')' in /xxx.php on line 11

 

Line 11 is:

 

for ($i = 1; $i <= $max; i++) {

[scootstah]

Sorry, missed a dollar. for ($i = 1; $i <= $max; $i++) {

 

I did look for about 5 minutes. It gave me a headache. Hence my question: "How do I turn glob() values into an array?" .. it wasn't long after that I started to feel nauseous.. so I decided to sit back, have a think -- and write up some code that I understand. I can see you're unimpressed, but my solution was to the best of my ability. I am not a very good programmer; but I try hard.

You're going to have to put more effort into learning programming than spending 5 minutes on a problem before giving up because you "feel nauseous". The manual and user contributed notes pretty much tells you what you need to do to use glob.

 

<?php

$dirs = array();

foreach(glob('[0-9]*', GLOB_ONLYDIR) as $dir) {
    if (!is_numeric($dir)) {
        continue;
    }

    $dirs[] = $dir;
}

echo max($dirs);

[Guest MrLeN]

This code works like a charm. And it's actually better than finding the highest folder, because if one of the 20 folders gets deleted, the code will replace it, instead of (theoretically) winding up at folder 2 million. There will always only be 20 folders - and never a gap in the numbers.

 

Thanks scootash. I appreciate your help

$max = 20;
 
for ($i = 1; $i <= $max; $i++) {
    $dir = $path . '/' . $i;
 
    if (!file_exists($dir)) {
        //echo 'Creating dir ' . $i;
        $new_category = $i;
        break;
    }
}

Edited September 9, 2015 by MrLeN