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Hello buddies,

 

I'm trying to create a form through wich one can add entries into DB. unfortunately, it works only with the first two text fields (Name, Geburtstag) and when I add additional field (Kontaktdetails) It won't work , when I get rid of the last one it functions greate.

even though the code seems to me ok.
what's the issue here.

 

thanks in advance

 

here is the insert.php

<table width="300" border="0" align="center" cellpadding="0" cellspacing="1">
<tr>
<td><form name="form1" method="post" action="insert_ac.php">
<table width="100%" border="0" cellspacing="1" cellpadding="3">
<tr>
<td colspan="3"><strong>Insert Data Into mySQL Database </strong></td>
</tr>

<tr>
<td width="71">Name</td>
<td width="6">:</td>
<td width="301"><input name="name" type="text" id="name"></td>
</tr>

<tr>
<td width="71">Geburtstag</td>
<td width="6">:</td>
<td width="301"><input name="Geburtstag" type="text" id="Geburtstag"></td>
</tr>


<tr>
<td width="71">Kontakdetails</td>
<td width="6">:</td>
<td width="301"><input name="kont" type="text" id="kont"></td>
</tr>

<tr>
<td colspan="3" align="center"><input type="submit" name="Submit" value="Submit"></td>
</tr>

</table>
</form>
</td>
</tr>
</table>

 insert_ac.php

<?php
error_reporting(0);
$host="localhost"; // Host name
$username="root"; // Mysql username
$password=""; // Mysql password
$db_name="test_db"; 
$tbl_name="worker3"; // Table name

mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");

$name=$_POST['name'];
$geburtstag=$_POST['Geburtstag'];
$kontakdetails=$_POST['kont'];

$sql="INSERT INTO $tbl_name(name, Geburtstag, kont) VALUES('$name', '$geburtstag', '$kontakdetails')";
$result=mysql_query($sql);

if($result){
echo "Successful";
echo "<BR>";
echo "<a href='insert.php'>Back to main page</a>";
}

else {
echo "ERROR";
}
?>

<?php
mysql_close();
?>
Link to comment
https://forums.phpfreaks.com/topic/298144-problem-with-the-text-fields/
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At face value the code above looks okay. If it's working without the 3rd field, my first guess is you don't have a column named "kont" in your database table (e.g. it doesn't exist, not spelled the same, etc.) or maybe it's not the right field type (e.g. you made it a date or int type and it's supposed to be text, or maybe you set it to be a certain length e.g. varchar(10) but attempting to put a 20 char value into it).

 

Do you have error reporting turned on? Are you getting an error(s)?

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