Dispaying one random image whenever page refreshed

[morrism35]

want to create a random image from these 5 images that I have in the template array every time I refresh the home page.

here is my code. my output has been : 

 

 

 

$dir = "Images";

  $DirEntries = scandir($dir, 1);

 

 

$template=preg_grep('/^download\d+\.(gif|png|jpg)$/', $DirEntries);

foreach($template as $temp){

 

shuffle($temp);

echo <IMG SRC="'. $temp.'"alt="alt">';

}

[Jacques1]

The code doesn't really make sense. You seem to have trouble understanding loops, which I already noticed in your previous thread.

 

If you want a single picture, then don't use a loop. The point of a foreach loop is to iterate over all elements. This also means you cannot shuffle $temp, because that's a particular element (in this case a path string).

 

Remove everything after the preg_grep() call and then select a random picture with array_rand().

[morrism35]

I understand about the foreach and I do know how to use the for loop, but for some reason it just didn't click in these situations

My book instructions told be to use shuffle()  in the instructions for the assignment. Array_rand isn't mentioned in my text book but I have seen it in searching for this issue. i will take a look at the array rand but not sure if my instructor will accept that.

[Jacques1]

If you're artificially restricted to shuffle(), you'd shuffle the array and then fetch the first element.

[morrism35]

what do we mean by fetch the first element. i've only been up to chapter 5 in this book.

[Jacques1]

shuffle($template);

echo $template[0];

You should use a better name than $template, though.

[morrism35]

Thank you I 'am only receiving one image but it is not displaying that image only a little image caption, like it knows

it's supposed to display an image but can't.

 

 

  $dir = "Images";

  $DirEntries = scandir($dir, 1);

 

 

$template=preg_grep('/^download\d+\.(gif|png|jpg)$/', $DirEntries);

 

shuffle($template);

 

 

echo '<img src=\$template[0]>'; 

[Barand]

The string you are echoing is in single quotes therefore the variable is not expanded. Use double quotes

echo "<img src='\$template[0]' >";

[morrism35]

echo "<img src='\$template[0]' >";   Threw an error: 

 

Parse error: syntax error, unexpected '\' (T_NS_SEPARATOR), expecting ',' or ';' in /homepages/6/d498253868/htdocs/morris/web182/ChineseZodiac/IncludesFolder/inc_footer.php on line 37

[Barand]

Make the directory separator / instead of \

[morrism35]

Parse error: syntax error, unexpected '">"' (T_CONSTANT_ENCAPSED_STRING), expecting ',' or ';' in/homepages/6/d498253868/htdocs/morris/web182/ChineseZodiac/IncludesFolder/inc_footer.php on line 37

 

thanks but still getting an error, been on this small part for 2 days.

 

 echo "<img src="/$template[0]">";

[Jacques1]

You cannot put raw double quotes into a double-quoted string. How is PHP supposed to figure out which ones are literal quotes and which ones are string delimiters?

 

If you insist on using double quotes for the HTML attributes (instead of single quotes as suggested by Barand), you'll have to escape them:

echo "<img src=\"/$template[0]\" alt=\"random image\">";

If this was serious code, you would of course have to HTML-escape the path before inserting it into the HTML attribute:

echo '<img src="/'.htmlspecialchars($template[0], ENT_QUOTES | ENT_SUBSTITUTE | ENT_HTML5, 'UTF-8').'" alt="random image">';

[morrism35]

echo "<img src=\"/$template[0]\" alt=\"random image\">"; I tried this code but it is just outputting the random image in text with a caption.

[Jacques1]

Are you absolutely sure that the path should have a leading slash? According to your original code, the images are actually in a subfolder called “Images”. In that case, the path needs to look like this:

Images/$template[0]

Otherwise, all images are searched directly in the document root.

[morrism35]

yes that is correct

[morrism35]

Hey it works. I need to go back and read or youtube sections on using single, double quotes, htmlentities, and escape characters. The syntax of php seems complicated and their seems to be a lot more code than say java. Maybe i'm wrong.

[morrism35]

Thank you so much.