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Get File Contents After a Line?


Guest MrLeN
Go to solution Solved by Guest MrLeN,

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<?php
//==Get URL's
 
 
$srcUrl='http://www.url.com';
$html = file_get_contents($srcUrl);
 
$dom = new DOMDocument();
@$dom->loadHTML($html);
 
// grab all the on the page
$xpath = new DOMXPath($dom);
 
//finding the a tag
$hrefs = $xpath->evaluate("/html/body//a");
 
//Loop to display all the links
for ($i = 0; $i < $hrefs->length; $i++) {
       $href = $hrefs->item($i);
       $url = $href->getAttribute('href');
  //Filter the null links
  if($url!='#')
  {
if (preg_match('/cars-vans-utes/',$url)) {
if (preg_match('/s-ad/',$url)) {
       echo $url / "<br />";
}
}
 
  }
}
 
?>

 

The above code works so that I can get all the URL's off a page.

 

However, I don't want the script to get absolutely every single link.

I want it to delete all the file content before a certain phrase in the HTML (say "abracadabra" for example)..

..and then display only the links that are positioned after the word "abracadabra" appears in the HTML.

Can anyone point me in the right direction to be able to do this?

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