Halisco Posted March 7, 2017 Share Posted March 7, 2017 (edited) I have two seperate tables containing an customer_id that match when a customer purchases a particular type of fruit. I have a multi table 1 "customers": customer_id email phone 1 email1@email.com 555-111-1111 2 email2@email.com 555-222-2222 3 email3@email.com 555-333-3333 customer_id type 1 macintosh 1 galla 2 galla 2 jonagold 3 jonagold Here is a shorter version of my item list i use for selecting the type of fruit i want to search for. <select name=fruit_type[] multiple> <option value="macintosh">macintosh</option> <option value="gala">a</option> <option value="jonagold">jonagold</option> </select> I then take that list and join it $search_fruit = filter_var_array($_POST['fruit_type'], FILTER_SANITIZE_SPECIAL_CHARS); $fruit_types = join("','", $search_fruit ); Here is my SQL query $search_criteria = "" . "SELECT c.* " . "FROM customers AS c LEFT JOIN type AS p ON c.customer_id= p.customer_id" . "WHERE type NOT IN ('$fruit_types ') " . "GROUP BY c.customer_id, p.customer_id" . "ORDER BY customer_id Asc"; This works if I Just use IN for the customers i want to find that have purchased a particular type of apple but i am trying to search for customers that have never purchased a particular apple or multiple apples from my list. For example if i select just macintosh from the list customer 1 still show up as not purchasing that apple type because they have purchased an apple that is not a macintosh. Can anyone help me figure out how i accomplish this task? Edited March 7, 2017 by Halisco Quote Link to comment https://forums.phpfreaks.com/topic/303382-mysql-left-join-single-row-not-found-in-a/ Share on other sites More sharing options...
taquitosensei Posted March 7, 2017 Share Posted March 7, 2017 select c.* from customers as c LEFT JOIN type as p on c.customer_id=p.customer_id where p.customer_id not in(select customer_id from type where type in('macintosh')); You'll have to do a nested query to select the ones that match, then select the ones that don't match from that. Quote Link to comment https://forums.phpfreaks.com/topic/303382-mysql-left-join-single-row-not-found-in-a/#findComment-1543887 Share on other sites More sharing options...
Solution NigelRel3 Posted March 7, 2017 Solution Share Posted March 7, 2017 You could use something like select c.* from customers c where not exists (select 1 from type t where c.customer_id = t.customer_id and t.type in ('macintosh')) All this does is find the people where a record isn't found for a set of types. Quote Link to comment https://forums.phpfreaks.com/topic/303382-mysql-left-join-single-row-not-found-in-a/#findComment-1543889 Share on other sites More sharing options...
taquitosensei Posted March 7, 2017 Share Posted March 7, 2017 (edited) You could use something like select c.* from customers c where not exists (select 1 from type t where c.customer_id = t.customer_id and t.type in ('macintosh')) All this does is find the people where a record isn't found for a set of types. Isn't that what he asked for? This works if I Just use IN for the customers i want to find that have purchased a particular type of apple but i am trying to search for customers that have never purchased a particular apple or multiple apples from my list. For example if i select just macintosh from the list customer 1 still show up as not purchasing that apple type because they have purchased an apple that is not a macintosh. Can anyone help me figure out how i accomplish this task? Edited March 7, 2017 by taquitosensei Quote Link to comment https://forums.phpfreaks.com/topic/303382-mysql-left-join-single-row-not-found-in-a/#findComment-1543890 Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.