Jump to content

Display only the current user's details using PHP and MySQL


ThirdYearChild
Go to solution Solved by Barand,

Recommended Posts

In this part of the code, both the score table and the profile page display everything I want, however, it is displaying EVERYBODIES details like

First Name Surname Email Category Username, However, I want it so that when the user is logged in they can only see THEIR OWN details

 

This is score.php

  <?php
error_reporting(E_ALL);
ini_set('display_errors', TRUE);
ini_set('display_startup_errors', TRUE);
require("db_connect.php");
session_start();
?>

<!doctype html>
<html lang="en">
  <head>
    <meta charset="utf-8">
    <meta name="viewport" content="width=device-width, initial-scale=1, shrink-to-fit=no">
    <meta name="description" content="">
    <meta name="author" content="">
    <link rel="icon" href="../../../../favicon.ico">

<?php
$con=mysqli_connect("localhost","username","Password","Database");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}


$result = mysqli_query($con,"SELECT * FROM Score where 'Username' LIKE _['Username']");


echo "<table border='1'>
<tr>
<th>ID</th>
<th>Username</th>
<th>Score</th>
<th>Gamedate</th>
<th>QuizTitle</th>
</tr>";

while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['ID'] . "</td>";
echo "<td>" . $row['Username'] . "</td>";
echo "<td>" . $row['Score'] . "</td>";
echo "<td>" . $row['Gamedate'] . "</td>";
echo "<td>" . $row['QuizTitle'] . "</td>";
echo "</tr>";
}
echo "</table>";

mysqli_close($con);
?>

this is profile.php

 <?php
 require('db_connect.php');
$result = mysqli_query($conn,"SELECT *FROM Users ");
while($row = mysqli_fetch_array($result))
{
       echo "<br />Your <b><i>Profile</i></b> is as follows:<br />";
        echo "<b>First name:</b> ". $row['FirstName'];
        echo "<br /><b>Last name:</b> ".$row['Surname'];
        echo "<br /><b>Email:</b> ".$row['Email'];
        echo "<br /><b>Year:</b> ".$row['Username'];
        echo "<br /><b>Date created :</b> ".$row['Date_Creation'];
}
mysqli_close($conn);
?>
    </main>



</html>

post-207960-0-13462200-1526683020_thumb.png profile.php

 

post-207960-0-82595000-1526683029_thumb.png Score.php

 

Link to comment
Share on other sites

  • Solution

How do you know which user is logged in? You have called session_start() but I see no references to any $_SESSION variables.

 

You should be storing the ID of the user on login then using that id in your queries. (... WHERE ID = $_SESSION['userid'] ) or, better yet, use a prepared query passing the id as a parameter.

 

You will be expecting only a single profile result so why have the while() loop? A single fetch is all you need.

 

 

SELECT * FROM Score where 'Username' LIKE _['Username']

The first mention of username in that query is a column name and should NOT be in quotes. Your syntax following LIKE is also wrong.

 

Don't use a nastyfrisk (SELECT * ) in your queries - specify the columns you need.

 

As for your error messages - if your $result contains a boolean (false) value then the query didn't work.

Link to comment
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.