Submit blank form message user to fill in, and if not found display!?

[suess0r]

OK,

i have pg1.php which has 3 dropdowns they can choose from with a button 'submit.' I have all of my queries running smoothly and correctly, i'm just having the following problems...

1. If they don't select anything and hit submit, it takes them to pg2.php - instead of displaying a message saying "Please select from atleast one of the following options" and not leaving the page.

2. If they do choose something and it runs the query and doesn't find anything, it doesn't say "Search Results not found..."
  ---i tried doing this if outside of my for loop
[quote]if (mysql_num_rows > 0) {

for ($i = 0; $i < mysql_num_rows($result_set); $i++)
{ -queries-}
} else {
echo 'Search Results not found...';[/quote]

*but unfortunately this kept returning Search Results not found... no matter what.*

hopefully someone can shed some light on these minor 2 problems. thanks!!  ;D

[SharkBait]

Prior to going to your second page you can try something like:
[code]
<?php

$errMsg = "";

//get infor from dropdown

if(!empty($_POST['mydropdown'])) {
  $value1 = $_POST['mydropdown];
} else {
  $errMsg .= "You forgot to select an option";
}

if($errMsg == "") {
  // No errors continue to page 2
} else {
  // There were errors display them:
  echo $errMsg;
}

?>
[/code]

If you need more explaination I can do so :)

[suess0r]

hmm, thanks sharkbait but i'm not POSTing the form to pg1.php i'm sending it to pg2.php where i could check to see if !empty to say that, but is there a way for me to stay in pg1.php to check if it's set on submission and if something is set to move on to pg2 with the post?? thanks for all the help!

[SharkBait]

Do you pass the variables via $_GET, $_SESSION, $_COOKIE or another way?