Icewolf Posted May 9, 2020 Share Posted May 9, 2020 Hi Can you please help me with an issue I am having? I have three description fields that I am pulling from a database. I did this so when it displays it isn't one long string. However the issue I am running into is if the 3rd description box is empty I do not what to display it. I cant figure out why it is only hitting the first display option. I created this variable $dishdesc3 = $_POST["dish_desc_3"]. I would like to say when it is NULL display the only the first 2 description boxes. Otherwise have it display all three description boxes. Is there a way to do that? <?php // Include the database configuration file require_once 'con_php.php'; //check connection if ($con -> connect_error){ die ("connection failed: " . $con -> connect_error); } $chsql = "SELECT * FROM dish_pic where cat_name = 'Chicken'"; $chresult = $con ->query($chsql); $dishdesc3 = $_POST["dish_desc_3"]; if ($chresult-> num_rows >0){ while ($row = $chresult -> fetch_assoc()){ if ($dishdesc3 = "3") { echo"<table border='0' cellpadding='4' cellspacing='0' width='100%'>"; echo" <tr><td class='style1' align='center' colspan='3' valign='top'>". $row["dish_name"] .".........................$" . $row["price"] . "<br><td></tr> <tr> <td class='style2' align='center' >" . $row["dish_desc"] . "<br> " . $row["dish_desc_2"] . "<br> <tr><td class='style3' align='center' >Serving " . $row["dish_size"] . " Calories " . $row["dish_cal"] . " Total Carbs " . $row["dish_tot_carbs"] . " Net Carbs " . $row["dish_net_carbs"] . " Fat " . $row["dish_fat"] . " Fiber " . $row["dish_fiber"] ." Protein " . $row["dish_protein"] . "<br></td></tr> <tr><td class='style2' align='center' >Recommend Side " . $row["dish_recommend"] . "</td></tr> <br> "; echo"</table>"; } Else { echo"<table border='0' cellpadding='4' cellspacing='0' width='100%'>"; echo" <tr><td class='style1' align='center' colspan='3' valign='top'>". $row["dish_name"] .".........................$" . $row["price"] . "<br><td></tr> <tr> <td class='style2' align='center' >" . $row["dish_desc"] . "<br> " . $row["dish_desc_2"] . "<br> " . $row["dish_desc_3"] . "<br></td></tr> <tr><td class='style3' align='center' >Serving " . $row["dish_size"] . " Calories " . $row["dish_cal"] . " Total Carbs " . $row["dish_tot_carbs"] . " Net Carbs " . $row["dish_net_carbs"] . " Fat " . $row["dish_fat"] . " Fiber " . $row["dish_fiber"] ." Protein " . $row["dish_protein"] . "<br></td></tr> <tr><td class='style2' align='center' >Recommend Side " . $row["dish_recommend"] . "</td></tr> <br> "; echo"</table>"; } } } $con->close(); ?> Quote Link to comment https://forums.phpfreaks.com/topic/310740-using-value-from-database-in-if-statement/ Share on other sites More sharing options...
Barand Posted May 9, 2020 Share Posted May 9, 2020 11 minutes ago, Icewolf said: if ($dishdesc3 = "3") That is setting the value to 3, not testing if it is equal to 3. The equality operator is "==" 1 Quote Link to comment https://forums.phpfreaks.com/topic/310740-using-value-from-database-in-if-statement/#findComment-1577779 Share on other sites More sharing options...
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