Moorcam Posted January 20, 2021 Share Posted January 20, 2021 Hi folks, This has been wrecking my brain. I did do a google a few times to see if I can find a solution but nothing unfortunately. I want to be able to update the details on a page without having to reupload a new image each time. But if I don't open a new image for upload, I cannot update any of the other details. Below is the code and form etc for this particular thing... Please note this is just a project and will not be going live. I know there are vulnerabilities and I will work on those at a later stage. Thanks for any help with this current issue. <?php include_once('includes/header.php'); if(isset($_POST['new']) && $_POST['new']==1){ if (isset($_POST['submit'])) { if(!empty($_FILES['image']['name'])) { // Get image name $image = $_FILES['image']['name']; $image = mysqli_real_escape_string($con, $_FILES['image']['name']); $slide_text = mysqli_real_escape_string($con, $_POST['slide_text']); $youtube = mysqli_real_escape_string($con, $_POST['youtube']); $vid_text = mysqli_real_escape_string($con, $_POST['vid_text']); // image file directory $target = "uploads/".basename($image); if($_POST['image'] = ""){ $sql = "UPDATE slide SET slide_text='".$slide_text."', image='".$image."', youtube='".$youtube."', vid_text='".$vid_text."'"; } else{ $sql = "UPDATE slide SET slide_text='".$slide_text."', youtube='".$youtube."', vid_text='".$vid_text."'"; } $result = mysqli_query($con, $sql); if (move_uploaded_file($_FILES['image']['tmp_name'], $target)) { $msg = "Image uploaded successfully"; }else{ $msg = "Failed to upload image"; } if(!$result){ die('Error: ' . mysqli_error($con)); } else{ $message = ' - <i class="fa fa-check success"> Record Updated!</i>'; } } } } $sql = "SELECT * FROM slide"; $result = $con->query($sql); if ($result->num_rows > 0) { while($row = $result->fetch_assoc()) { ?> <!-- Header--> <div class="breadcrumbs"> <div class="col-sm-4"> <div class="page-header float-left"> <div class="page-title"> <h1>Slide Show</h1> </div> </div> </div> <div class="col-sm-8"> </div> </div> <div class="content mt-3"> <div class="animated fadeIn"> <div class="row"> <div class="col-lg-12"> <div class="card"> <div class="card-header"><strong>Image </strong><small>Slide</small></div> <div class="card-body card-block"> <form role="form" method="post" action"" enctype="multipart/form-data"> <input type="hidden" name="new" value="1" /> <div class="modal-body"> <div class="row form-group"> <div class="col-6"> <div class="form-group"><label for="image" class=" form-control-label">Image</label> <input type="file" id="image" name="image" value="<?php echo $row['image']; ?>" class="form-control"> </div> </div> <div class="col-6"> <div class="form-group"><label for="name" class=" form-control-label">Uploaded Image</label> <img src="uploads/<?php echo $row['image']; ?>" width="150" height="150" class="img-fluid hover-shadow" /> </div> </div> </div> <div class="row form-group"> <div class="col-6"> <div class="form-group"><label for="youtube" class=" form-control-label">Video</label> <input type="text" id="youtube" name="youtube" value="<?php echo $row['youtube']; ?>" placeholder="Enter Video URL" class="form-control"> </div> </div> <div class="col-6"> <div class="form-group"><label for="vid_text" class=" form-control-label">Video Text</label> <input type="text" id="vid_text" name="vid_text" value="<?php echo $row['vid_text']; ?>" placeholder="Video Text" class="form-control"> </div> </div> </div> <div class="form-group"><label for="slide_text" class=" form-control-label">Text Overlay</label> <textarea is="slide_text" name="slide_text" class="form-control"><?php echo $row['slide_text']; ?></textarea> </div> <div class="modal-footer"> <button type="submit" name="submit" id="submit" class="btn btn-primary">Confirm</button> </div> </form> </div> </div> </div><!-- .animated --> </div><!-- .content --> <?php } } ?> </div><!-- /#right-panel --> <!-- Right Panel --> <script src="assets/js/vendor/jquery-2.1.4.min.js"></script> <script src="assets/js/popper.min.js"></script> <script src="assets/js/plugins.js"></script> <script src="assets/js/main.js"></script> <script src="assets/js/lib/data-table/datatables.min.js"></script> <script src="assets/js/lib/data-table/dataTables.bootstrap.min.js"></script> <script src="assets/js/lib/data-table/dataTables.buttons.min.js"></script> <script src="assets/js/lib/data-table/buttons.bootstrap.min.js"></script> <script src="assets/js/lib/data-table/jszip.min.js"></script> <script src="assets/js/lib/data-table/pdfmake.min.js"></script> <script src="assets/js/lib/data-table/vfs_fonts.js"></script> <script src="assets/js/lib/data-table/buttons.html5.min.js"></script> <script src="assets/js/lib/data-table/buttons.print.min.js"></script> <script src="assets/js/lib/data-table/buttons.colVis.min.js"></script> <script src="assets/js/lib/data-table/datatables-init.js"></script> <script src="https://cdn.tiny.cloud/1/sw6bkvhzd3ev4xl3u9yx3tzrux4nthssiwgsog74altv1o65/tinymce/5/tinymce.min.js" referrerpolicy="origin"></script> <script> tinymce.init({ selector: 'textarea', plugins: 'advlist autolink lists link image charmap print preview hr anchor pagebreak', toolbar_mode: 'floating', }); </script> <script type="text/javascript"> $(document).ready(function() { $('#customer-table').DataTable(); } ); </script> </body> </html> As you can see I am trying to use an If clause if the image field in the form is empty then I just want to update the other details. Else, if I fill the image field with a file, then update the lot. if($_POST['image'] = ""){ $sql = "UPDATE slide SET slide_text='".$slide_text."', image='".$image."', youtube='".$youtube."', vid_text='".$vid_text."'"; } else{ $sql = "UPDATE slide SET slide_text='".$slide_text."', youtube='".$youtube."', vid_text='".$vid_text."'"; } This doesn't work. Any ideas, besides give up? Â Quote Link to comment https://forums.phpfreaks.com/topic/312027-cannot-update-mysqli-unless-i-upload-image/ Share on other sites More sharing options...
Barand Posted January 20, 2021 Share Posted January 20, 2021 1 hour ago, DanEthical said: This doesn't work. What exactly does that mean? What happens, or doesn't happen. Quote Link to comment https://forums.phpfreaks.com/topic/312027-cannot-update-mysqli-unless-i-upload-image/#findComment-1583920 Share on other sites More sharing options...
Moorcam Posted January 20, 2021 Author Share Posted January 20, 2021 12 minutes ago, Barand said: What exactly does that mean? What happens, or doesn't happen. Hi mate, Nothing happens. No errors etc. If I just update some text and click submit, nothing happens. But, if I load a new image into the file input and click update, any changes to text are successful. What I am trying to achieve is for me to be able to change text without having to upload a new image each time. Quote Link to comment https://forums.phpfreaks.com/topic/312027-cannot-update-mysqli-unless-i-upload-image/#findComment-1583921 Share on other sites More sharing options...
Solution Barand Posted January 20, 2021 Solution Share Posted January 20, 2021 Both updates happen only when if(!empty($_FILES['image']['name'])) { ... 1 Quote Link to comment https://forums.phpfreaks.com/topic/312027-cannot-update-mysqli-unless-i-upload-image/#findComment-1583923 Share on other sites More sharing options...
Moorcam Posted January 20, 2021 Author Share Posted January 20, 2021 21 minutes ago, Barand said: Both updates happen only when if(!empty($_FILES['image']['name'])) { ... DOH!!! Makes sense and works. // image file directory $target = "uploads/".basename($image); if(!empty($_FILES['image']['name'])) { $sql = "UPDATE slide SET slide_text='".$slide_text."', image='".$image."', youtube='".$youtube."', vid_text='".$vid_text."'"; } else{ $sql = "UPDATE slide SET slide_text='".$slide_text."', youtube='".$youtube."', vid_text='".$vid_text."'"; } $result = mysqli_query($con, $sql); Thanks man. Quote Link to comment https://forums.phpfreaks.com/topic/312027-cannot-update-mysqli-unless-i-upload-image/#findComment-1583924 Share on other sites More sharing options...
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