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I am trying to pass a php variable to javascript but it's not working. This is the "sketch" of my code.

<?php
$url="asset/go/";
?>

 

<!DOCTYPE html>
<html>
    <head>
        <title>Page Title</title>
        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>

    </head>
    <body>
        <script>
            var user="mayor";
            var url ='<?php echo json_encode($url); ?>';
       if(user=="mayor"){
           alert(url);
       }
        </script>
    </body>
</html>

As it is now, it comes with the output below:

<?php echo json_encode($url); ?>

If I remove the quotation around the php in d jQuery, it throws an error in syntax.

Also both codes are located in the same file named test.php

Thanks in advance.

Edited by Abel1416
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https://forums.phpfreaks.com/topic/312485-php-variable-not-been-passed-to-jquery/
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13 minutes ago, Abel1416 said:

It is a php file. test.php

My PHP test file 

<?php
$url="asset/go/";
?>
<!DOCTYPE html>
<html>
    <head>
        <title>Page Title</title>
        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>

    </head>
    <body>
        <script>
            var user="mayor";
            var url ='<?php echo json_encode($url); ?>';
       if(user=="mayor"){
           alert(url);
       }
        </script>
    </body>
</html>

Here is mu result

<--  view-source:http://localhost/test/312485.php -->
<!DOCTYPE html>
<html>
    <head>
        <title>Page Title</title>
        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>

    </head>
    <body>
        <script>
            var user="mayor";
            var url ='"asset\/go\/"';
       if(user=="mayor"){
           alert(url);
       }
        </script>
    </body>
</html>

 

So except for the extra quotes it seems fine

I can't seem to get the unparsed php code.

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