null00 Posted October 25, 2021 Share Posted October 25, 2021 (edited) Hi, so I have been trying to get this to work but I haven't been able to. I am supposed to do this: "Using the Sakila database, give me a combined list of films that have an actor with the last name Depp and the actors in the film Ace Goldfinger. Order the output by type ascending." I have this coded and yet it will not return what I need it to. SELECT NOW() firstlastname, CONCAT(actor.first_name,' ', actor.last_name) AS film_or_actor , 'Actor' AS type FROM actor INNER JOIN film_actor ON actor.actor_id = film_actor.actor_id INNER JOIN film ON film_actor.film_id = film.film_id INNER JOIN film_text ON film_text.title = film.title INNER JOIN film_list ON film.film_id = film_list.FID WHERE actor.last_name LIKE '%depp%' UNION SELECT NOW() firstlastname, film.title AS film_or_actor, 'Film' AS type FROM actor INNER JOIN film_actor ON actor.actor_id = film_actor.actor_id INNER JOIN film ON film_actor.film_id = film.film_id INNER JOIN film_text ON film_text.title = film.title INNER JOIN film_list ON film.film_id = film_list.FID WHERE film_list.actors IN film.film_id = 2 ORDER BY type ASC; any help would be appreciated. Edited October 25, 2021 by gizmola Code tag Quote Link to comment https://forums.phpfreaks.com/topic/314107-sakila-database-help/ Share on other sites More sharing options...
Barand Posted October 25, 2021 Share Posted October 25, 2021 (edited) 36 minutes ago, null00 said: WHERE film_list.actors IN film.film_id = 2 What is that supposed to achieve? Edited October 25, 2021 by Barand Quote Link to comment https://forums.phpfreaks.com/topic/314107-sakila-database-help/#findComment-1591399 Share on other sites More sharing options...
Barand Posted October 25, 2021 Share Posted October 25, 2021 try SELECT f.title as film_or_actor , concat(a.first_name, ' ', a.last_name) as `Search for` , 'Film' as `type` FROM film f JOIN film_actor fa USING (film_id) JOIN actor a USING (actor_id) WHERE a.last_name LIKE '%depp%' UNION SELECT concat(a.first_name, ' ', a.last_name) , f.title , 'Actor' FROM film f JOIN film_actor fa USING (film_id) JOIN actor a USING (actor_id) WHERE f.film_id = 2 ORDER BY `type`, film_or_actor; Quote Link to comment https://forums.phpfreaks.com/topic/314107-sakila-database-help/#findComment-1591403 Share on other sites More sharing options...
gizmola Posted October 25, 2021 Share Posted October 25, 2021 @Barand: The way the question is posed, isn't the clearest, but I think what is wanted is a list of films that a) has an actor named "depp" or "featured any of the actors in film_id = 2". The result set should be films and not films or actors. I based this off the initial description: 6 hours ago, null00 said: "Using the Sakila database, give me a combined list of films..." Quote Link to comment https://forums.phpfreaks.com/topic/314107-sakila-database-help/#findComment-1591417 Share on other sites More sharing options...
gizmola Posted October 25, 2021 Share Posted October 25, 2021 My take on this, is that it makes more sense if you can break it down into problems: 1. What list of actors (actor_id) do you need? You need actors with a name like "depp" AND actors who were in the 'ACE GOLDFINGER film". This 1st query gets you those actors. SELECT actor_id FROM actor WHERE last_name like '%depp%' UNION SELECT actor_id FROM film_actor WHERE film_id = (SELECT film_id FROM film WHERE title = 'ACE GOLDFINGER'); To get the full list of films, you need to get all the films for any of those actors, so you have to join your list of actors to the film_actor table, so one very simple way to think about this, is to use some subqueries fed into the upper query. The original query, can be used as a subquery to get you the list of actors. SELECT DISTINCT f.film_id, f.title FROM film f JOIN film_actor fa ON f.film_id = fa.film_id WHERE fa.actor_id IN (SELECT actor_id FROM actor WHERE last_name LIKE '%depp%' UNION SELECT actor_id FROM film_actor WHERE film_id = (SELECT film_id FROM film WHERE title = 'ACE GOLDFINGER') ) ORDER BY f.title; Here's another syntactical take, joining to the subquery rather than using IN SELECT DISTINCT f.film_id, f.title FROM film f JOIN film_actor fa ON f.film_id = fa.film_id JOIN (SELECT actor_id FROM actor WHERE last_name LIKE '%depp%' UNION SELECT actor_id FROM film_actor WHERE film_id = (SELECT film_id FROM film WHERE title = 'ACE GOLDFINGER') ) as a ON fa.actor_id = a.actor_id ORDER BY f.title; And here's a version, where the 'ACE GOLDFINGER' query is also a join to a subquery. This one is probably a bit more correct, in the case that there was more than one 'ACE GOLDFINGER" titled film, that might have different actors. SELECT DISTINCT f.film_id, f.title FROM film f JOIN film_actor fa ON f.film_id = fa.film_id JOIN (SELECT actor_id FROM actor WHERE last_name LIKE '%depp%' UNION SELECT actor_id FROM film_actor JOIN (SELECT film_id FROM film WHERE title = 'ACE GOLDFINGER' ) as ace ON film_actor.film_id = ace.film_id ) as a ON fa.actor_id = a.actor_id ORDER BY f.title; 1 Quote Link to comment https://forums.phpfreaks.com/topic/314107-sakila-database-help/#findComment-1591418 Share on other sites More sharing options...
Barand Posted October 25, 2021 Share Posted October 25, 2021 I prefer to JOIN to the subquery - it should be faster SELECT DISTINCT f.film_id, f.title FROM film f JOIN film_actor fa ON f.film_id = fa.film_id JOIN (SELECT actor_id FROM actor WHERE last_name LIKE '%depp%' UNION SELECT actor_id FROM film_actor WHERE film_id = (SELECT film_id FROM film WHERE title = 'ACE GOLDFINGER') ) actid USING (actor_id) ORDER BY f.title; 1 Quote Link to comment https://forums.phpfreaks.com/topic/314107-sakila-database-help/#findComment-1591419 Share on other sites More sharing options...
Barand Posted October 25, 2021 Share Posted October 25, 2021 Yep, definitely faster. Timing results... IN subquery 0.0666 seconds JOIN subquery 0.0012 seconds Quote Link to comment https://forums.phpfreaks.com/topic/314107-sakila-database-help/#findComment-1591420 Share on other sites More sharing options...
gizmola Posted October 26, 2021 Share Posted October 26, 2021 8 minutes ago, Barand said: Yep, definitely faster. Timing results... IN subquery 0.0666 seconds JOIN subquery 0.0012 seconds Yes, much faster, but why? The explains are nice (since we're conducting a mini- mysql class here 😃. I do like your application of USING ... really nice reduction of syntax, although the plans are exactly the same if you utilize the full ON syntax. Nested Subquery: MariaDB [sakila]> explain SELECT DISTINCT f.film_id, f.title -> FROM film f -> JOIN film_actor fa ON f.film_id = fa.film_id -> WHERE fa.actor_id IN -> (SELECT actor_id -> FROM actor -> WHERE last_name LIKE '%depp%' -> UNION -> SELECT actor_id -> FROM film_actor -> WHERE film_id = -> (SELECT film_id FROM film WHERE title = 'ACE GOLDFINGER') -> ) -> ORDER BY f.title; +------+--------------------+------------+--------+------------------------+----------------+---------+------------------+------+----------------------------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +------+--------------------+------------+--------+------------------------+----------------+---------+------------------+------+----------------------------------------------+ | 1 | PRIMARY | f | index | PRIMARY | idx_title | 514 | NULL | 934 | Using index; Using temporary; Using filesort | | 1 | PRIMARY | fa | ref | idx_fk_film_id | idx_fk_film_id | 2 | sakila.f.film_id | 1 | Using where; Using index; Distinct | | 2 | DEPENDENT SUBQUERY | actor | eq_ref | PRIMARY | PRIMARY | 2 | func | 1 | Using where | | 3 | DEPENDENT UNION | film_actor | eq_ref | PRIMARY,idx_fk_film_id | PRIMARY | 4 | func,const | 1 | Using where; Using index | | 4 | SUBQUERY | film | ref | idx_title | idx_title | 514 | const | 1 | Using where; Using index | | NULL | UNION RESULT | <union2,3> | ALL | NULL | NULL | NULL | NULL | NULL | | +------+--------------------+------------+--------+------------------------+----------------+---------+------------------+------+----------------------------------------------+ 6 rows in set (0.00 sec) Join to Subquery: MariaDB [sakila]> explain SELECT DISTINCT f.film_id, f.title -> FROM film f -> JOIN film_actor fa ON f.film_id = fa.film_id -> JOIN -> (SELECT actor_id -> FROM actor -> WHERE last_name LIKE '%depp%' -> UNION -> SELECT actor_id -> FROM film_actor -> WHERE film_id = -> (SELECT film_id FROM film WHERE title = 'ACE GOLDFINGER') -> ) actid USING (actor_id) -> ORDER BY f.title; +------+--------------+------------+--------+------------------------+---------------------+---------+-------------------+------+---------------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +------+--------------+------------+--------+------------------------+---------------------+---------+-------------------+------+---------------------------------+ | 1 | PRIMARY | <derived2> | ALL | NULL | NULL | NULL | NULL | 204 | Using temporary; Using filesort | | 1 | PRIMARY | fa | ref | PRIMARY,idx_fk_film_id | PRIMARY | 2 | actid.actor_id | 1 | Using index | | 1 | PRIMARY | f | eq_ref | PRIMARY | PRIMARY | 2 | sakila.fa.film_id | 1 | | | 2 | DERIVED | actor | index | NULL | idx_actor_last_name | 182 | NULL | 200 | Using where; Using index | | 3 | UNION | film_actor | ref | idx_fk_film_id | idx_fk_film_id | 2 | const | 4 | Using where; Using index | | 4 | SUBQUERY | film | ref | idx_title | idx_title | 514 | const | 1 | Using where; Using index | | NULL | UNION RESULT | <union2,3> | ALL | NULL | NULL | NULL | NULL | NULL | | +------+--------------+------------+--------+------------------------+---------------------+---------+-------------------+------+---------------------------------+ Quote Link to comment https://forums.phpfreaks.com/topic/314107-sakila-database-help/#findComment-1591423 Share on other sites More sharing options...
Barand Posted October 26, 2021 Share Posted October 26, 2021 Joins to a table subquery are faster than dependent subqueries. The "IN subquery" version has one of those in the explain Quote Link to comment https://forums.phpfreaks.com/topic/314107-sakila-database-help/#findComment-1591424 Share on other sites More sharing options...
gizmola Posted October 26, 2021 Share Posted October 26, 2021 Since we are talking about these plans and optimizations, I think it's good to point this out to @null00 You should always avoid using "LIKE '%something%'". This type of query can not use an index. The explains show this clearly. MariaDB [sakila]> select count(*) from actor; +----------+ | count(*) | +----------+ | 200 | +----------+ So you have 200 rows in your actor table, and even though it attempts to utilize the idx_actor_last_name index on actor, the explain shows that even with a join to the subquery, the portion that looks for '%depp%' "table scans" all 200 rows. +------+--------------+------------+--------+------------------------+---------------------+---------+-------------------+------+---------------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +------+--------------+------------+--------+------------------------+---------------------+---------+-------------------+------+---------------------------------+ | 2 | DERIVED | actor | index | NULL | idx_actor_last_name | 182 | NULL | 200 | Using where; Using index | +------+--------------+------------+--------+------------------------+---------------------+---------+-------------------+------+---------------------------------+ I removed all the query plan steps, except for the part that searches for '%depp%' and you can see in the rows column that it examines all 200 rows. So long as a string can be searched from left to right, wildcards can be used and a btree index is still useful. So if this query is modified to be 'depp%' then it will no longer table scan the actor table, but instead will find the only actor row that matches. MariaDB [sakila]> explain SELECT DISTINCT f.film_id, f.title -> FROM film f -> JOIN film_actor fa ON f.film_id = fa.film_id -> JOIN -> (SELECT actor_id -> FROM actor -> WHERE last_name LIKE 'depp%' -> UNION -> SELECT actor_id -> FROM film_actor -> WHERE film_id = -> (SELECT film_id FROM film WHERE title = 'ACE GOLDFINGER') -> ) actid USING (actor_id) -> ORDER BY f.title; +------+--------------+------------+--------+------------------------+---------------------+---------+-------------------+------+---------------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +------+--------------+------------+--------+------------------------+---------------------+---------+-------------------+------+---------------------------------+ | 1 | PRIMARY | <derived2> | ALL | NULL | NULL | NULL | NULL | 6 | Using temporary; Using filesort | | 1 | PRIMARY | fa | ref | PRIMARY,idx_fk_film_id | PRIMARY | 2 | actid.actor_id | 1 | Using index | | 1 | PRIMARY | f | eq_ref | PRIMARY | PRIMARY | 2 | sakila.fa.film_id | 1 | | | 2 | DERIVED | actor | range | idx_actor_last_name | idx_actor_last_name | 182 | NULL | 2 | Using where; Using index | | 3 | UNION | film_actor | ref | idx_fk_film_id | idx_fk_film_id | 2 | const | 4 | Using where; Using index | | 4 | SUBQUERY | film | ref | idx_title | idx_title | 514 | const | 1 | Using where; Using index | | NULL | UNION RESULT | <union2,3> | ALL | NULL | NULL | NULL | NULL | NULL | | +------+--------------+------------+--------+------------------------+---------------------+---------+-------------------+------+---------------------------------+ 7 rows in set (0.00 sec) Really when you look at it, for this query, a wildcard search of name doesn't make much sense, even with 'depp%', but I guess this is for homework/test prep. In general, you never want to use LIKE '%something%'. If you need full text search then use a fulltext engine or mysql's FULLTEXT indexing and searching syntax. Quote Link to comment https://forums.phpfreaks.com/topic/314107-sakila-database-help/#findComment-1591441 Share on other sites More sharing options...
Barand Posted October 26, 2021 Share Posted October 26, 2021 Weird! I see your results have 7 rows. When I run it I get 124 rows mysql> SELECT DISTINCT f.film_id, f.title -> FROM film f -> JOIN film_actor fa ON f.film_id = fa.film_id -> JOIN -> (SELECT actor_id -> FROM actor -> WHERE last_name LIKE 'depp%' -> UNION -> SELECT actor_id -> FROM film_actor -> WHERE film_id = -> (SELECT film_id FROM film WHERE title = 'ACE GOLDFINGER') -> ) actid USING (actor_id) -> ORDER BY f.title; +---------+-------------------------+ | film_id | title | +---------+-------------------------+ | 2 | ACE GOLDFINGER | | 3 | ADAPTATION HOLES | | 11 | ALAMO VIDEOTAPE | | 14 | ALICE FANTASIA | | 17 | ALONE TRIP | | 43 | ATLANTIS CAUSE | | 72 | BILL OTHERS | | 85 | BONNIE HOLOCAUST | | 92 | BOWFINGER GABLES | | 100 | BROOKLYN DESERT | . . . | 883 | TEQUILA PAST | | 895 | TOMORROW HUSTLER | | 901 | TRACY CIDER | | 909 | TREASURE COMMAND | | 919 | TYCOON GATHERING | | 925 | UNITED PILOT | | 944 | VIRGIN DAISY | | 950 | VOLUME HOUSE | | 954 | WAKE JAWS | | 957 | WAR NOTTING | | 960 | WARS PLUTO | | 967 | WEEKEND PERSONAL | | 979 | WITCHES PANIC | | 991 | WORST BANGER | | 992 | WRATH MILE | +---------+-------------------------+ 124 rows in set (0.02 sec) There are 43 films starring a "Depp" before starting on the other actors from Ace Goldfinger mysql> SELECT COUNT(DISTINCT film_id) FROM film_actor WHERE actor_id IN (100, 160); +-------------------------+ | COUNT(DISTINCT film_id) | +-------------------------+ | 43 | +-------------------------+ 1 row in set (0.01 sec) I've noticed in past projects that MariaDB can be a bit flaky with table subqueries. Don't know if that's the case here Quote Link to comment https://forums.phpfreaks.com/topic/314107-sakila-database-help/#findComment-1591443 Share on other sites More sharing options...
Barand Posted October 26, 2021 Share Posted October 26, 2021 @gizmola What results do you get if you put the subquery results into a temp table and use that CREATE TEMPORARY TABLE temp_actor (actor_id smallint not null primary key); -- -- INSERT INTO temp_actor SELECT actor_id FROM actor WHERE last_name LIKE 'depp%' UNION SELECT actor_id FROM film_actor WHERE film_id = (SELECT film_id FROM film WHERE title = 'ACE GOLDFINGER'); -- -- SELECT DISTINCT f.film_id , f.title FROM film f JOIN film_actor fa USING (film_id) JOIN temp_actor USING (actor_id) ORDER BY f.title; I get the same as before (124 recs) Quote Link to comment https://forums.phpfreaks.com/topic/314107-sakila-database-help/#findComment-1591444 Share on other sites More sharing options...
Barand Posted October 26, 2021 Share Posted October 26, 2021 OK - I'm senile. 7 rows in the explain results!!! 1 Quote Link to comment https://forums.phpfreaks.com/topic/314107-sakila-database-help/#findComment-1591446 Share on other sites More sharing options...
gizmola Posted October 27, 2021 Share Posted October 27, 2021 5 hours ago, Barand said: OK - I'm senile. 7 rows in the explain results!!! No worries my friend. I hope others enjoy this thread as much as we did. I don't interact with too many people that have as much interest in SQL/Rdbms, relational design and theory, and db internals as we do. Always a pleasure, and frequently an educational experience to read your posts! Quote Link to comment https://forums.phpfreaks.com/topic/314107-sakila-database-help/#findComment-1591452 Share on other sites More sharing options...
Barand Posted October 27, 2021 Share Posted October 27, 2021 7 hours ago, gizmola said: I hope others enjoy this thread as much as we did I agree. It's great to have a discussion and knowledgable interaction about a problem rather than just delivering straight answer to a topic. Quote Link to comment https://forums.phpfreaks.com/topic/314107-sakila-database-help/#findComment-1591462 Share on other sites More sharing options...
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