Days until a date

[Rohit265]

Hello, How can I get number of days remaining to a date, which does not add year,

For ex, In this code, I will have to change the year (2022) once Christmas date passes, but I do not want to change the year every time.

$futureDate = '2022-12-25';
$d = new DateTime($futureDate);
echo $d->diff(new DateTime())->format('%a');  //--> 321

printf("\n");
 

[Barand]

Try

$futureDate = new DateTime('dec 25');
$now = new DateTime('today');

if ($now > $futureDate) {
    $futureDate->modify('+1 year');
}
echo $now->diff($futureDate)->days;