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Output "legit" error messages

Kairu

By Kairu
in PHP Coding Help

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Kairu Member

Kairu

Posted
Posted
Alright.... What I'm trying to do, (as some of you know by now, since I've been here for a week or so) is create an image dynamically with URL's and coordinates from a database.

I have used a .htaccess file to all but hide the fact that it is PHP, and now need help in creating a legit 404 error (Meaning my server returns a "file not found" or other if the file is not called correctly.

This is what I tried first, but it did not work, because I forgot to take into account that each browser has a different way of handling the error messages.

[code]<?php

function hide()
{

echo "<!DOCTYPE HTML PUBLIC \"-//IETF//DTD HTML 2.0//EN\">\n";
echo "<html><head>\n";
echo "<title>404 Not Found</title>\n";
echo "</head><body>\n";
echo "<h1>Not Found</h1>\n";
echo "<p>The requested URL " . $_SERVER['REQUEST_URI'] . " was not found on this

server.</p>\n";
echo "</body></html>\n";
exit();
}

mysql_connect('localhost:3306', 'User', 'Pass');

mysql_select_db('gaia_image');

$result = mysql_query('SELECT * FROM data WHERE id = ' . $_GET['id']);

$row = mysql_fetch_array($result);

if ($row[0] == "")
{
hide();
}
elseif(strpos($_SERVER['REQUEST_URI'], 'image.php') != FALSE)
{
hide();
}
elseif($_GET['ext'] == "jpeg" || $_GET['ext'] == "jpg")
{
header('content-type: image/jpeg');
}
elseif($_GET['ext'] == "png")
{
header('content-type: image/png');
}
elseif($_GET['ext'] == "gif")
{
header('content-type: image/gif');
}
else
{
hide();
}


$sig = $row[1];
$n = $row[2];
$image = array(); $avi = array(); $avi_width = array(); $avi_height = array(); $dest_x =

array(); $dest_y = array(); $a = array();

for ($i=0; $i<=$n; $i++)
{
array_push($a, $row[(($i * 3) + 3)]);
}

for ($i=0; $i<=$n-1; $i++)
{
array_push($avi, imagecreatefrompng($a[$i]));
array_push($avi_width, imagesx($avi[$i]));
array_push($avi_height, imagesy($avi[$i]));
}

array_push($image, imagecreatefromstring(file_get_contents($sig)));

if ($row[33] != "1")
{
array_push($image, imagecreatefromstring(file_get_contents($sig)));
}

$size = getimagesize($sig);

for ($i=0; $i<=$n; $i++)
{
$temp = "\$temp = " . $row[(($i * 3) + 4)] . ";"; //Some of the rows that are called here
eval($temp);                                                //are actually formulas on how to get the
array_push($dest_x , $temp );                        //coordinates instead of exact coordinates,
$temp = "\$temp = " . $row[(($i * 3) + 5)] . ";"; //so this is what I came up with to avoid
eval($temp);                                                //any problems that may arise.
array_push($dest_y , $temp );
}

for ($i=0; $i<=$n-1; $i++)
{
imagecopy($image[0], $avi[$i], $dest_x[$i] , $dest_y[$i], 0, 0, $avi_width[$i],

$avi_height[$i]);
imagedestroy($avi[$i]);
}

if ($row[33] != "1")
{
imagecopy($image[0], $image[1], 0, 0, 0, 0, $size[0], $size[1]);
imagedestroy($image[1]);
}

if($_GET['ext'] == "jpeg" || $_GET['ext'] == "jpg")
{
imagejpeg($image[0]);
}
elseif($_GET['ext'] == "png")
{
imagepng($image[0]);
}
elseif($_GET['ext'] == "gif")
{
imagegif($image[0]);
}

imagegif($image[0]);
imagedestroy($image[0]);

?>[/code]

(I am also open to suggestions on ways of "stream lining" my code)

The file name is "image.php", but when it is called properly it is not. In essence what I am trying to do is remove all ways of figuring out if the file is php or a real image. Any suggestions off topic on how to do this are also welcome.

Now to my question. Is there a way to mimic the results a server outputs when a file or folder is not found?
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