MOnkman Posted April 9, 2003 Share Posted April 9, 2003 When using this: $_player_num = 15; $query = \"select * from players where player_num = \'%\".$_player_num.\"%\'\"; I get no results however, when using ........player_num like \'......... instead i get a returned result for this but it would also return a result had $_player_num been 5, even though it didnt exist. I am confused and frustrated, please help!!! Link to comment https://forums.phpfreaks.com/topic/329-problem-with-select-using-instead-of-like/ Share on other sites More sharing options...
DocSeuss Posted April 9, 2003 Share Posted April 9, 2003 You can\'t use wildcards \"%\" in an = SELECT what exactly are you trying to find matches for if it\'s anything with a \'15\' in it use. $query = \"SELECT * FROM palyers WHERE player_num LIKE \'%$_player_num%\'\"; Link to comment https://forums.phpfreaks.com/topic/329-problem-with-select-using-instead-of-like/#findComment-1062 Share on other sites More sharing options...
Recommended Posts
Archived
This topic is now archived and is closed to further replies.