thedust2010 Posted January 8, 2007 Share Posted January 8, 2007 I am trying to execute FFMPEG via PHP's exec() command with the following code:[code] $output = array(); $cmd = exec("ffmpeg -i /path/to/website/test_media/tortoise.avi -ab 56 -ar 22050 -b 500 -r 15 -s 320x240 /path/to/website/test_media/tortoise_success.flv", $output); echo "--<br>"; echo nl2br($cmd) . "<br>"; print_r($output); echo "<br>--";[/code]When I enter in this command logged into the shell it works, but when I try this out in PHP, I get no output from the code above. Instead it just yields:[code]--Array ( )--[/code]I have tried an absolute path to ffmpeg but that hasn't made a difference. Any ideas what might be wrong here? Why am I not getting any kind of output (success/failure) from this? Quote Link to comment Share on other sites More sharing options...
thedust2010 Posted January 8, 2007 Author Share Posted January 8, 2007 Never mind, I got it to work... just needed to change permissions on the folder! Oops! Quote Link to comment Share on other sites More sharing options...
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