pctechtime Posted January 23, 2007 Share Posted January 23, 2007 Below is what I have so far. My problem is I want select the clients name and number and view all of the infomation stored for that client in all the rows in the database. This must be in a table format with headers that I can name. Example clients_name would be Customers Name. Thanks for your help.Mike <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"><head><meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /><title>Untitled Document</title></head><body><?php $usr = "888"; $pwd = "888"; $db = "888"; $host = "localhost"; // # connect to database $cid = mysql_connect($host,$usr,$pwd); mysql_select_db($db); if (mysql_error()) { print "Database ERROR: " . mysql_error(); }// Create the pull-down menu information.$query1 = "SELECT order_number,client_name,test_ordered,salesperson,order_date FROM orders ORDER BY order_number ASC";$result1 = @mysql_query ($query1);$pulldown1 = '<option>Select One</option>';while ($row = mysql_fetch_array ($result1, MYSQL_ASSOC)) {$pulldown1 .= "<option value=\"{$row['order_number']}\">{$row['order_number']}) {$row['test_ordered']}</option>\n";} ?><form name="orders" action="orderlookup.php" method="POST"> <table> <tr><td>Order Name: </td><td><select name="order_number"><?php echo $pulldown1; ?> </select> </td></tr></table><p><input type="submit" value="View Results"></p></th></tr></table></form><?php// this is processed when the form is submitted // back on to this page (POST METHOD) if ($_SERVER['REQUEST_METHOD'] == "POST") { # escape data and set variables $order_number = addslashes($_POST["order_number"]); $client_name = addslashes($_POST["client_name"]); $test_ordered = addslashes($_POST["test_ordered"]); $salesperson = addslashes($_POST["salesperson"]); $order_date = addslashes($_POST["order_date"]); }?></body></html> Quote Link to comment Share on other sites More sharing options...
simcoweb Posted January 23, 2007 Share Posted January 23, 2007 Hi. I'm a bit confused with the code since it appears that your form drop down selector is going to have one big choice of all three of those options in one option. $pulldown1 = '<option>Select One</option>';Then two lines down you concatenate it with two other choices:$pulldown1 .= "<option value=\"{$row['order_number']}\">{$row['order_number']}) {$row['test_ordered']}</option>\n";If I read this right it will produce a display of one option containing all three choices. Or maybe i'm not reading that right?Getting information displayed about a particular row (or in this case a particular person) only requires you have the query specify a unique identifier...like an 'id' field.[code]$query1 = "SELECT * FROM orders WHERE id='$id' ";[/code]Where the 'id' is passed in your search form. Or, the order_id or whatever you want to search by. Make sense?Then, that query would work like this:[code]<?php$query1 = "SELECT * FROM orders WHERE id='$id' ";$results = mysql_query($query1);echo "<table><tr> <th>Field 1</th><th>Field 2</th><th>Field 3</th><th>Field 4</th> </tr>";while ($row = mysql_fetch_array($results)){ echo "<tr><td>" . $row['field1'] . "</td><td>" . $row['field2'] . "</td><td>" . $row['field3'] . "</td><td>" . $row['field4'] . "</td> </tr>";}echo "</table>\n";?>[/code]That will produce a table with field names at the top (the <th> tags) and a row for each result (presumably one row). Quote Link to comment Share on other sites More sharing options...
pctechtime Posted January 25, 2007 Author Share Posted January 25, 2007 This still doesn't fix the problem here are my answeres to your questionsHi. I'm a bit confused with the code since it appears that your form drop down selector is going to have one big choice of all three of those options in one option. $pulldown1 = '<option>Select One</option>'; [b]This make the Select One show up first in the drop down menu.[/b]Then two lines down you concatenate it with two other choices:$pulldown1 .= "<option value=\"{$row['order_number']}\">{$row['order_number']}) {$row['test_ordered']}</option>\n"; [b]This make the all of the rows show up in the drop down to show up order_number first and then ) and then the test_ordered in the drop down menu. example " 4) Gold "[/b]If I read this right it will produce a display of one option containing all three choices. Or maybe i'm not reading that right? This makes the above show up. Now I want to select number 4 Gold. When I press the button I want all the rows and colums data to show up in a list that where item_number 4 shows up only. remember 4 Gold was my selection above. Below is the code I have now.<?php $usr = "***"; $pwd = "***"; $db = "***"; $host = "localhost"; // # connect to database $cid = mysql_connect($host,$usr,$pwd); mysql_select_db($db); if (mysql_error()) { print "Database ERROR: " . mysql_error(); }// Create the pull-down menu information.$query1 = "SELECT order_number,client_name,test_ordered,salesperson,order_date FROM orders ORDER BY order_number ASC";$result1 = @mysql_query ($query1);$pulldown1 = '<option>Select One</option>';while ($row = mysql_fetch_array ($result1, MYSQL_ASSOC)) {$pulldown1 .= "<option value=\"{$row['order_number']}\">{$row['order_number']}) {$row['test_ordered']}</option>\n";} ?><form name="orders" action="orderlookup.php" method="POST"> <table> <tr><td><b>Order Name: </b></td><td><select name="order_number"><?php echo $pulldown1; ?> </select> </td></tr></table><p><input type="submit" value="View Results"></p></th></tr></table></form><?php$query1 = "SELECT * FROM orders WHERE order_number='$order_number' ";$results = mysql_query($query1);echo "<table><tr> <th>Order Number</th> <th>Client Name</th> <th>Test Ordered</th> <th>Date Ordered</th> <th>Sales Person</th> </tr>";while ($row = mysql_fetch_array($results)){ echo "<tr><td>" . $row['order_number'] . "</td><br><td>" . $row['client_name'] . "</td><td>" . $row['test_ordered'] . "</td><td>" . $row['order_date'] . "</td><td>" . $row['salesperson'] . "</td> </tr>";}echo "</table>\n";?></body></html> Quote Link to comment Share on other sites More sharing options...
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