GD Image Creation

[Miichael]

Hello

I have a question regarding the GD library image creation functions.

I can create the images I want using the php library functions.  No problem.  The result is the image on a web page displayed in my browser.

However I cannot figure out how to capture said image and so I can place it on my web page where I want.

I've spen hours looking but can find no answers.  Can anyone offer any suggestions?

Thanks

Michael

[bqallover]

What you want is something like this in your HTML...

[code]
<img src="imagecreator.php">
[/code]

...where imagecreator.php is the script that actually outputs the image.  You can of course pass in GET variables on a quiery string like...

[code]
<img src="imagecreator.php?bgcol=white&fgcol=green">
[/code]

...which is nice! :)

[HuggieBear]

Another alternative, if you want to use it in multiple places, you could create the image like you are and save it.

Depending on the type of image you're creating, you'll have a line that looks something like this, that outputs the image to the browser:

[code=php:0]imagejpeg($im);[/code] or
[code=php:0]imagejpeg($im, null, 100);[/code]

By changing, or adding the second parameter, you can save the image.

[code=php:0]$filename = '/home/domains/domain.co.uk/images/dynamic.jpg';
imagejpeg($im, $filename, 100);[/code]

Regards
Huggie

[Miichael]

Thanks

Both suggestions are good.  I actually tried '<img src="imagecreator.php">' as it is most appropriate for my needs.

And when the code renders I get a broken image symbol and the the html code is '<img src="imagecreator.php">'

For some reason the php script will not be invoked, but I know it is ok because if I call it directly the image is created and displayed.

[HuggieBear]

You must output a header in imagecreator.php, like this:

[code=php:0]header("Content-type: image/jpg");[/code]

Of course this will change depending on the type of image you're outputting.

Regards
Huggie

[Miichael]

I must really be doing something wrong, 'cause I did that also.

Basically my code looks like this

the referenenced php file:

<?php

$im = imagecreatefrompng("path/iimage_name");

//some processing going on... (and I've deleted the processing in my test case to eliminate an error injection there)

header("Content-type: image/png");
imagepng($im);
ImageDestroy($im);
?>

in the calling program, in php I have the following code (I'm using the phpBB template)

$processed_image = '<img src="includes/make_the_image.php" alt="">'

and then

'"I_IMAGE' => $processed_image

and in my template file the code is

{I_IMAGE}

and when I render my code looks like:

<img src="includes/make_the_image.php" alt=""> and of course yields a broken image

Ive played around with the php code, for example trying to something like

src = "' . includes/make_the_image.php . ' "

and

src = "' . includes(includes/make_the_image.php) . '"

but to no avail.  I'm sure I'm missing something really simple (or have yet to learn it, this is my first time trying this kind of thing, but darned if I've seen it yet.

Thank you for your responses.

Mike

[HuggieBear]

The code you have looks fine, and if you view the source and get the result that you've pasted then the only conclusion is that the 'processing' you've cut out is causing an issue of some kind.

Regards
Huggie