ra2833 Posted January 25, 2007 Share Posted January 25, 2007 well, i have made tremendous progress on this small project thanks to all of you who have helped..... Information: 1. i am able to upload a file as binary data to a database 2. i am able to retrieve all relevent information from the database 2.a like the name i gave the file 2.b like the size of the file 2.c like the unique identifer of the file 2.d like the type of file But, when i pull out the binary data from the database, i get stream of information on my screen instead of the image!!!!!! can someone help me out here: <?php//same connection structure to database as previous post (above) //$faq_unique_id_r = intval( $_GET['faq_unique_id_s'] ); $image_unique_id_r = 92; mysql_select_db($database_faqSQLconn, $faqSQLconn); $query = "SELECT * FROM faq_image WHERE faq_image.image_unique_id = '".$image_unique_id_r."'"; $faq_image_result = mysql_query($query, $faqSQLconn) or die("Query failed: " . mysql_error() . " Actual query: " . $query);?><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Untitled Document</title> </head> <body> <?php $row = mysql_fetch_array($faq_image_result); echo $row['image_unique_id']; echo $row['name']; echo $row['file_type']; echo $row['image']; <----- this does not print image ?> </body> Quote Link to comment Share on other sites More sharing options...
HuggieBear Posted January 25, 2007 Share Posted January 25, 2007 Maybe you need to use something like [url=http://uk.php.net/manual/en/function.imagecreatefromstring.php]imagecreatefromstring()[/url]RegardsHuggie Quote Link to comment Share on other sites More sharing options...
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