concatenation problem...I think

[dwest]

[code]

foreach($_POST['hid_price'.$id] as $price)
{
$total = ($price*$qty);
}[/code]

Note the $id tacked on to "hid_price"...the result being hid_price1, 2, etc.

How would I go about tacking the value of $id on to the $total variable name so I get a corresponding variable named $total1, $total2, etc.?

Thanks!

[pocobueno1388]

[code]
$_POST['hid_price'.$id]
[/code]

I'm pretty sure you can't do that. I'm not exactly sure what your trying to do...if you want to print out hid_price1 you would do:

[code]
echo $hid_price.$id;
[/code]

Why do you even want to include the ID in your foreach statement? All it deals with is the price and quantity. Maybe I am just not understanding...

[dwest]

Well, best not to worry with why as it is a long answer and not relevant to the question. ;)

Let me attempt to make the question a bit more simple.

I have a variable called $var.
I want a new variable called $var1.

The "1"  in the variable name $var1, should be the value held in $id.

So in effect I want to create a dynamic variable NAME to be used in the code.  Not a dynamic variable.

Make sense?

Any way to do that?

Thanks!

[dwest]

Would $var{$id} create a variable with the name of  $var plus whatever the value of $id is?

[spfoonnewb]

[code]$_POST["hid_price$id"][/code]