Passing variables, only variable names are printed

[2eXtreme]

Hey guys!

 

Im having trouble sending variables to another php file. This is the code for the php file that sends the data:

 

$number=2;

$number2=3;

header('Location:http://mysite.com/get.php?num=$number&num2=$number2');

 

the receiving file, get.php, is meant to receive the value of $number and ouput it to a .txt file. The code is:

 

$digit = $_GET["num"];

$digit2 = $_GET["num2"];

$log = fopen("log.txt", "a");

fwrite($log, $digit."\n");

fwrite($log, $digit2."\n");

fclose($log);

 

but all the log file contains is:

 

$number

$number2

 

When what I want to be seeing is:

 

2

3

 

Im guessing this comes down to how I've passed the variables in the sending file to the receiving file. Can anyone please tell me what I have to change? Thanks very much for any help given!

 

[Balmung-San]

Use:

 

'Location:http://mysite.com/get.php?num='.$number.'&num2=.'$number2

[.josh]

it's because you are using single quotes instead of double quotes in your header function call. Single quotes interprets the variable names literally. If you want php to look at the variables as variables, use double quotes

[2eXtreme]

Thank you so much! I knew it was about separting the variables up, like in Java and C, but using ',' and '+' didnt work, so I was totally stumped! Thanks so much!