n8w Posted February 27, 2006 Share Posted February 27, 2006 [!--sizeo:4--][span style=\"font-size:14pt;line-height:100%\"][!--/sizeo--][b]I am trying to return all the rows with the user_id 1699when I do it without the join it returns the correct number of 24[/b][!--sizec--][/span][!--/sizec--]SQL STATEMENT[code]SELECT *FROM favoritesWHERE `user_id` = "1699"LIMIT 0 , 30[/code]Results[code] Edit Delete 2006-02-26 22:00:31 1699 846 1 Edit Delete 2006-02-26 23:09:19 1699 848 1 Edit Delete 2006-02-26 23:09:40 1699 850 1 Edit Delete 2006-02-26 23:30:49 1699 859 1 Edit Delete 2006-02-27 01:41:37 1699 870 1 Edit Delete 2006-02-27 09:42:33 1699 896 1 Edit Delete 2006-02-27 00:24:47 1699 920 1 Edit Delete 2006-02-27 09:51:57 1699 926 1 Edit Delete 2006-02-26 22:30:10 1699 927 1 Edit Delete 2006-02-27 03:22:03 1699 974 1 Edit Delete 2006-02-27 00:25:49 1699 981 1 Edit Delete 2006-02-27 00:26:14 1699 1043 1 Edit Delete 2006-02-27 03:19:02 1699 1067 1 Edit Delete 2006-02-27 01:51:55 1699 1144 1 Edit Delete 2006-02-27 01:51:24 1699 1164 1 Edit Delete 2006-02-27 03:18:33 1699 1179 1 Edit Delete 2006-02-27 01:40:27 1699 1210 1 Edit Delete 2006-02-27 09:52:38 1699 1256 1 Edit Delete 2006-02-27 01:20:47 1699 1384 1 Edit Delete 2006-02-27 02:24:00 1699 1471 1 Edit Delete 2006-02-26 23:18:11 1699 1539 1 Edit Delete 2006-02-27 01:20:47 1699 1587 1 Edit Delete 2006-02-27 03:18:02 1699 1679 1 Edit Delete 2006-02-26 23:08:34 1699 1984 1[/code][!--sizeo:4--][span style=\"font-size:14pt;line-height:100%\"][!--/sizeo--][b]But when I do it with a join .. it leaves some of them out for some reason .. it only returns 17 rows .. can you see a problem with my SQL statement?[/b][!--sizec--][/span][!--/sizec--][code]Showing rows 0 - 16 (17 total, Query took 0.9221 sec)SQL query: SELECT a . * , b.avg, b.total_votes, c.clicks, d . * , e.total_favoritesFROM illustrators_table aLEFT JOIN users d ON a.user_id = d.user_idLEFT JOIN (SELECT user_id, AVG( score ) AS avg, COUNT( * ) AS total_votesFROM score_tableGROUP BY user_id)b ON a.user_id = b.user_idLEFT JOIN (SELECT user_id, COUNT( * ) AS clicksFROM external_urlWHERE str_date > curdate( ) - INTERVAL 14DAY GROUP BY user_id)c ON a.user_id = c.user_idLEFT JOIN (SELECT illustrator_id, user_id, COUNT( illustrator_id ) AS total_favoritesFROM favoritesGROUP BY illustrator_id)e ON a.user_id = e.illustrator_idWHERE visible = "t" && s_verified = "t" && e.user_id = "1699"GROUP BY c.user_idORDER BY a.user_id DESCLIMIT 0 , 200[/code]Results[code]removed [/code] Quote Link to comment https://forums.phpfreaks.com/topic/3675-unexpected-sql-query-results/ Share on other sites More sharing options...
wickning1 Posted February 27, 2006 Share Posted February 27, 2006 When you do it in the join, you are losing user_id information because you are grouping on illustrator_id. I am trying to discern what you want from this query. I'm guessing that you want to know how many people have selected the user 1699 as one of their favorite illustrators. Is that correct?[code]SELECT a.* , b.avg, b.total_votes, c.clicks, d.* , e.total_favoritesFROM illustrators_table aLEFT JOIN users d ON a.user_id = d.user_idLEFT JOIN ( SELECT user_id, AVG(score) AS avg, COUNT(*) AS total_votes FROM score_table WHERE user_id="1699" GROUP BY user_id) b ON a.user_id = b.user_idLEFT JOIN ( SELECT user_id, COUNT( * ) AS clicks FROM external_url WHERE str_date > curdate( ) - INTERVAL 14 DAY AND user_id="1699" GROUP BY user_id) c ON a.user_id = c.user_idLEFT JOIN ( SELECT illustrator_id, COUNT(*) AS total_favorites FROM favorites WHERE illustrator_id="1699" GROUP BY illustrator_id) e ON a.user_id = e.illustrator_idWHERE visible = "t" && s_verified = "t" && a.user_id="1699"[/code] Quote Link to comment https://forums.phpfreaks.com/topic/3675-unexpected-sql-query-results/#findComment-12741 Share on other sites More sharing options...
n8w Posted February 27, 2006 Author Share Posted February 27, 2006 hey Wickning1 thanks for responding .. you are always so helpfulThe result I am looking for is .. it to return all the the records that the user_id 1699 marked as their favorites .. which would be illustrator_id 846,848,850,etcI tried the statement from your previous post and this is what it returned[a href=\"http://www.illustrationmundo.com/illustrators3.php?favorites=1699\" target=\"_blank\"]http://www.illustrationmundo.com/illustrat...?favorites=1699[/a]just the user 1699 Here are the correct results .. but can't seem to get them when I am doing a jointable structure (ent_date,user_id, illustrator_id,status)ent_date= date entereduser_id= the person that is dong the action of adding another person as one of their favoritesillustrator_id= the person they added .. the artist they likedstatus=0 is delete from table .. 1 is add .. don't really need this column[code] Edit Delete 2006-02-26 22:00:31 1699 846 1 Edit Delete 2006-02-26 23:09:19 1699 848 1 Edit Delete 2006-02-26 23:09:40 1699 850 1 Edit Delete 2006-02-26 23:30:49 1699 859 1 Edit Delete 2006-02-27 01:41:37 1699 870 1 Edit Delete 2006-02-27 09:42:33 1699 896 1 Edit Delete 2006-02-27 00:24:47 1699 920 1 Edit Delete 2006-02-27 09:51:57 1699 926 1 Edit Delete 2006-02-26 22:30:10 1699 927 1 Edit Delete 2006-02-27 03:22:03 1699 974 1 Edit Delete 2006-02-27 00:25:49 1699 981 1 Edit Delete 2006-02-27 00:26:14 1699 1043 1 Edit Delete 2006-02-27 03:19:02 1699 1067 1 Edit Delete 2006-02-27 10:20:26 1699 1082 1 Edit Delete 2006-02-27 01:51:55 1699 1144 1 Edit Delete 2006-02-27 01:51:24 1699 1164 1 Edit Delete 2006-02-27 03:18:33 1699 1179 1 Edit Delete 2006-02-27 01:40:27 1699 1210 1 Edit Delete 2006-02-27 09:52:38 1699 1256 1 Edit Delete 2006-02-27 01:20:47 1699 1384 1 Edit Delete 2006-02-27 02:24:00 1699 1471 1 Edit Delete 2006-02-26 23:18:11 1699 1539 1 Edit Delete 2006-02-27 01:20:47 1699 1587 1 Edit Delete 2006-02-27 03:18:02 1699 1679 1 Edit Delete 2006-02-26 23:08:34 1699 1984 1[/code] Quote Link to comment https://forums.phpfreaks.com/topic/3675-unexpected-sql-query-results/#findComment-12844 Share on other sites More sharing options...
wickning1 Posted February 27, 2006 Share Posted February 27, 2006 Ok, so you just want a count of how many favorites they've picked? That's easy enough.Now, if you're actually wanting to know WHICH illustrators are their favorites, you are better off doing a second query than trying to combine it into this one.[code]SELECT a.* , b.avg, b.total_votes, c.clicks, d.* , e.total_favoritesFROM illustrators_table aLEFT JOIN users d ON a.user_id = d.user_idLEFT JOIN ( SELECT user_id, AVG(score) AS avg, COUNT(*) AS total_votes FROM score_table WHERE user_id="1699" GROUP BY user_id) b ON a.user_id = b.user_idLEFT JOIN ( SELECT user_id, COUNT( * ) AS clicks FROM external_url WHERE str_date > curdate( ) - INTERVAL 14 DAY AND user_id="1699" GROUP BY user_id) c ON a.user_id = c.user_idLEFT JOIN ( SELECT user_id, COUNT(*) AS total_favorites FROM favorites WHERE user_id="1699" GROUP BY user_id) e ON a.user_id = e.user_idWHERE visible = "t" && s_verified = "t" && a.user_id="1699"[/code] Quote Link to comment https://forums.phpfreaks.com/topic/3675-unexpected-sql-query-results/#findComment-12849 Share on other sites More sharing options...
n8w Posted February 27, 2006 Author Share Posted February 27, 2006 ahhh .. thanks .. that's all I needed to hear .. should I just write another query in this page .. or should I just create a new my_favorites.php page? The count is working corectly .. I am trying to provide a way for people to find illustrators they like ..so the count reflects how many people added them .. not the other way around.Thanks for your help!!! Quote Link to comment https://forums.phpfreaks.com/topic/3675-unexpected-sql-query-results/#findComment-12853 Share on other sites More sharing options...
wickning1 Posted February 27, 2006 Share Posted February 27, 2006 Ahh so you want all of user 1699's favorites to be printed on screen, with all of their info. I finally understand what you're after. Here's the fastest way I can think of:[code]SELECT a.* , b.avg, b.total_votes, c.clicks, d.*FROM illustrators_table aINNER JOIN users d ON a.user_id = d.user_idINNER JOIN ( SELECT s.user_id, AVG(s.score) AS avg, COUNT(*) AS total_votes FROM score_table s INNER JOIN favorites e ON e.illustrator_id = s.user_id WHERE e.user_id = "1699" GROUP BY s.user_id) b ON a.user_id = b.user_idINNER JOIN ( SELECT u.user_id, COUNT(*) AS clicks FROM external_url u INNER JOIN favorites e ON e.illustrator_id = u.user_id WHERE str_date > curdate() - INTERVAL 14 DAY AND e.user_id = "1699" GROUP BY u.user_id) c ON a.user_id = c.user_idWHERE visible = "t" && s_verified = "t"[/code] Quote Link to comment https://forums.phpfreaks.com/topic/3675-unexpected-sql-query-results/#findComment-12866 Share on other sites More sharing options...
n8w Posted February 27, 2006 Author Share Posted February 27, 2006 [b]thats it!!!!!!!!!!!!!!!!!!!!!![/b][size=5]awesome .. thanks so so much .. I can't express my gratitude... thanks! Quote Link to comment https://forums.phpfreaks.com/topic/3675-unexpected-sql-query-results/#findComment-12875 Share on other sites More sharing options...
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