joebudden Posted February 2, 2007 Share Posted February 2, 2007 Hi guys, i just want to know if this is possible, or if any one has a simple solution..... ok, iv got a form with a drop down box which has three values <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <select> <option>Heavy training with emphasis on strength and stamina</option> <option>Medium training with emphasis on fast paced attacking football</option> <option>Light training focused on quick passing and set piece play</option> </select> <input type="submit" value="Begin Training Session" /> </form> Say the user selects "Heavy training with emphasis on strength and stamina"..... is there any way of inserting a "1" into a database table and so on for the others??? Anyone know if its possible ??? thanks in advance Link to comment https://forums.phpfreaks.com/topic/36764-solved-drop-down-boxes/ Share on other sites More sharing options...
ted_chou12 Posted February 2, 2007 Share Posted February 2, 2007 I think you need something like: <option value="test">Heavy training with emphasis on strength and stamina</option> you need the value= as well... Ted Link to comment https://forums.phpfreaks.com/topic/36764-solved-drop-down-boxes/#findComment-175345 Share on other sites More sharing options...
joebudden Posted February 2, 2007 Author Share Posted February 2, 2007 hmmmm so I have <select> <option value="1">Heavy training with emphasis on strength and stamina</option> <option value="2">Medium training with emphasis on fast paced attacking football</option> <option value="3">Light training focused on quick passing and set piece play</option> </select> but then how would I implement if(isset statements to insert the values into my DB??? Il have a look on the net but if anyone knows please reply!!! cheers Link to comment https://forums.phpfreaks.com/topic/36764-solved-drop-down-boxes/#findComment-175350 Share on other sites More sharing options...
ted_chou12 Posted February 2, 2007 Share Posted February 2, 2007 <?php if(isset($_POST['submit'])){ $type = $_POST['type']; //...mysql insert or whatever you want... } ?> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <select name="type"> <option>Heavy training with emphasis on strength and stamina</option> <option>Medium training with emphasis on fast paced attacking football</option> <option>Light training focused on quick passing and set piece play</option> </select> <input type="submit" name="submit" value="Begin Training Session" /> </form> I think thats basically it. Ted Link to comment https://forums.phpfreaks.com/topic/36764-solved-drop-down-boxes/#findComment-175405 Share on other sites More sharing options...
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