markkanning Posted February 2, 2007 Share Posted February 2, 2007 Hey folks, I may have a variable declaration problem with a script I'm tearing my hair out about. The script is checking whether or not a variable has been passed. If it has, it builds a page based on a series of functions that use that variable for MySQL stuff. If the variable hasn't been passed, it builds another page with a <select> dropdown in a form whose action will re-run the same page with the passed variable. The problem is I keep getting an error from both IE and Firefox that says the page with the "?variable=1" appended to the URL is "Invalid". Even if I hardcode the URL into the address bar like "http://www.domain.com/page.php?stationid=1", it gives me the "Invalid" error. I know the URL is technically just fine, which makes me think the script itself is bunkus. Here's the initial page: <?php include ($_SERVER['DOCUMENT_ROOT'].'/config.php'); //If stationid has been passed, display admin page if(isset($_GET['stationid'])) { adminHeader(); chooseDisplayStation(); adminBoxContent(); adminFooter(); } //Check if stationid has been passed - If not, give them the "choose station" dialogue box else { adminHeader(); chooseStation(); adminBoxSecurity(); echo "<center><b>Welcome to the Website Administration Console.</b><br>\n Please choose a station to edit in the station box above.</center>"; adminFooter(); } ?> Each page being built by the previous script has a "Choose Station" form that looks like this: <form action="<?php echo $_SERVER['PHP_SELF']; ?>" name="choosestation"> <select onchange="document.location.href=this.options[this.selectedIndex].value;"> <option> -- </option> <?php include ($_SERVER['DOCUMENT_ROOT'].'/db/dbconnect.php'); $query = "select * from stations order by stationid"; $result = mysql_query($query); $num_results = mysql_num_rows($result); for ($i=0; $i < $num_results; $i++) { $row = mysql_fetch_array($result); echo "<option value=\"?stationid=".stripslashes($row["stationid"])."\">".stripslashes($row["stationname"])."</option>\n"; } ?> </select> </form> So far changing anything about the <form> yields no results, making me think it's just fine. However, in the first page, I've changed the "isset" code with some different results. I've changed this: if(isset($_GET['stationid'])) to this: if(isset($_POST['stationid'])) and I don't get the error. However, I also don't get the variable passed, either, and end up with the first "Choose Station" page over and over. Anyone got some input? Quote Link to comment Share on other sites More sharing options...
marcus Posted February 2, 2007 Share Posted February 2, 2007 Change <select onchange="document.location.href=this.options[this.selectedIndex].value;"> to <select onchange="document.location.href=this.options[this.selectedIndex].value;" name="stationid"> You simply left out the drop downs' name so it wouldn't pass the variable because it wasn't given. Quote Link to comment Share on other sites More sharing options...
markkanning Posted February 2, 2007 Author Share Posted February 2, 2007 I've actually tried that. It doesn't make a difference and it shouldn't being that the <option> value is the "?stationid=". I also tried adding the <select name="stationid"> with <option value=".stripslashes($row["stationid"])."> and that only passing in the URL like "http://www.domain.com/1" which, of course, does nothing. *sigh* Quote Link to comment Share on other sites More sharing options...
marcus Posted February 2, 2007 Share Posted February 2, 2007 Haha. You need a form method. Change: <form action="<?php echo $_SERVER['PHP_SELF']; ?>" name="choosestation"> To: <form action="<?php echo $_SERVER['PHP_SELF']; ?>" name="choosestation" method="get"> Quote Link to comment Share on other sites More sharing options...
markkanning Posted February 2, 2007 Author Share Posted February 2, 2007 Um...I think I gave you an older version of that <form> code because I've since added the method="get" and, well...no luck there, either. Same result. Does it have something to do with this... <?php echo $_SERVER['PHP_SELF']; ?> Is there another method of posting a script to itself that parses the URL differently? Quote Link to comment Share on other sites More sharing options...
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