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Schlo_50

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I had a webpage that had code to display some items from a database, i then changed the layout and then copied and pasted the working code into the new layout and now the script won't work.. Im sure it's exactly the same code, but now when i run the script all i get is my layout load up with none of the items in my database displayed!

 

<quote>

<?

$host = 'correct' ;

$user = 'correct' ;

$pass = 'correct' ;

$db = 'correct' ;

$table = 'correct' ;

$show_all = 'SELECT * FROM stock_tbl' ;

 

mysql_connect ($host,$user,$pass) or die ( mysql_error ());

mysql_select_db ($db)or die ( mysql_error ());

$result = mysql_query ($show_all) or die ( mysql_error ());

while ($row = mysql_fetch_array ($result))

{

   echo $row['st_id']. ' - <img src="'. $row['image'] . '" />' . $row['descr'] . ' - ' . $row['price'] . "<br />\n";

}

?>

</quote>

 

Anything painfully wrong here?

Thanks guys!

 

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Dont forget to connect to the DB before executing the select statement.

 

Also  I always use "mysql_free_result($result); " after the while loop

 

$show_all = 'SELECT * FROM stock_tbl' ;

$result = mysql_query ($show_all) or die ( mysql_error ());

while ($row = mysql_fetch_assoc($result)) {

 

    echo $row['st_id']. ' - <img src="'. $row['image'] . '" />' . $row['descr'] . ' - ' . $row['price'] . "

\n";

}

mysql_free_result($result);

?>

 

Hope this helps,  :)

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Some times if you don't use '<?php' to open it can trip. I don't think your getting an error but I catch em this way.. (uncomment if you want the error)

 

function do_mysql_query($s, $conn)
{
try
{
	if ( !@ ($res = mysql_query($s, $conn)) )
		throw new Exception (mysql_error());
}
catch (Exception $e)
{
	//$sret .= 'Could not create table because: ' . $e->getMessage();
	return array(-1, $res);
}
return array(0, $res);
}

 

Is php working here at all, if so try outputting intermediaries, or other data from populated tables, etc...

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Still, nothing is being displayed from my database..Im using the code on a separate page with no formatting at all and all that shows is a plain white bg.  ???

 

 

<?php

$host = 'mysql2.freehostia.com' ;

$user = 'correct' ;

$pass = 'correct' ;

$db = 'correct' ;

$table = 'stock_tbl' ;

$show_all = 'SELECT * FROM stock_tbl' ; 

$result = mysql_query ($show_all) or die ( mysql_error ());

while ($row = mysql_fetch_assoc($result)) {

 

    echo $row['st_id']. ' - <img src="'. $row['image'] . '" />' . $row['descr'] . ' - ' . $row['price'] . "

\n";

}

mysql_free_result($result);

?>

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This connection string may be helpful in finding the error,

 

<?php

 

$conn = mysql_connect("correcthost", "correctuser", "correctpassword");

if (!$conn) {

  echo "Unable to connect to DB: " . mysql_error();

  exit;

}

if (!mysql_select_db("correct")) {

  echo "Unable to select Database: " . mysql_error();

  exit;

}

$show_all = 'SELECT * FROM stock_tbl' ;

 

$result = mysql_query($show_all );

 

if (!$result) {

  echo "Could not successfully run query ($sql) from DB: " . mysql_error();

  exit;

}

if (mysql_num_rows($result) == 0) {

  echo There are no rows found";

  exit;

}

$num_results = mysql_num_rows($result);

// echo above $num_results to check rows returned

 

while ($row = mysql_fetch_assoc($result)) {

  echo $row['st_id']. ' - <img src="'. $row['image'] . '" />' . $row['descr'] . ' - ' . $row['price'] .,"<br>";

}

mysql_free_result($result);

 

?>

 

 

Keep going! ;)

 

If this does not work, could you post your table structure...

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Ok i pasted the code you used and changed the host, username and password etc to the correct details and now all that appears is the script..lol I wish i wasn't a n00b!  :P (I have enclosed a pic)

 

<url>http://img154.imageshack.us/img154/4446/untitledqx4.jpg</url>

 

Here is what i think you mean by table structures:

 

<url>http://img154.imageshack.us/img154/3129/untitledmf0.jpg</url>

 

Thanks.

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I am going to try and replicate your table and test it, but how are you storing your images, or is this just a link to your image. Also, have you worked with this server before?

 

I have never seen the code reappear in that manner unless it was pasted into a WYSIWIG screen. What are you using for an editor?

 

 

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Look at the following page:  http://66.223.105.215/pictures.php

 

 

<?php
$conn= mysql_connect("localhost" ,"uname" ,"password" ) ; 
if(!$conn) {
echo "Unable to connect to DB: " . mysql_error(); 
exit;
} 
if (!mysql_select_db("gallery")) { 
echo " Unable to select gallery Database: " . mysql_error() ; 
exit; 
} 
$sql = "SELECT * FROM stock_tbl";
$result = mysql_query( $sql); 
if ( mysql_num_rows($result) == 0) { 
echo "No Documents Available at this time";
} else { 
$num_results = mysql_num_rows($result) ; 
echo "There are currently", $num_results, " images available<br>"; 
while ( $row = mysql_fetch_assoc( $result)) { 

echo $row["st_id"], " - <img src=", $row["image"], " /><br>", $row["descr"], " - ",  $row["price"] ,"<br>";

?> 
<?php
echo "<br>";
} } 
mysql_free_result($result); 
?> 

 

 

 

It was created from the following schema:

 

#

# Table structure for table `stock_tbl`

#

 

CREATE TABLE `stock_tbl` (

  `st_id` int(11) NOT NULL auto_increment,

  `name` varchar(15) NOT NULL default '',

  `image` varchar(255) NOT NULL default '',

  `descr` text NOT NULL,

  `stock` enum('No','Yes') NOT NULL default 'No',

  `dateadd` date NOT NULL default '0000-00-00',

  `price` tinytext NOT NULL,

  KEY `st_id` (`st_id`)

) TYPE=MyISAM AUTO_INCREMENT=2 ;

 

#

# Dumping data for table `stock_tbl`

#

 

INSERT INTO `stock_tbl` VALUES (1, 'Sloop', 'DSC_2691.JPG', 'Picture from my sailing trip', 'No', '2007-02-05', 'N/A');

   

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