jscix Posted February 11, 2007 Share Posted February 11, 2007 Ok, If I should not be using this forum for easy questions like these, please just tell me. I'm only a couple days into learning so i'm doing alot of thing's wrong here. Ok, how could I re-write this, so that PHP Inserts the value of the variables instead of the actual text $dbusr and $dbpw. Again I'm sorry for asking something, that's probably extreamly easy.. $query = 'CREATE TABLE `$dbusr` ( `$dbusr` varchar(26) NOT NULL, PRIMARY KEY (`$dbusr`) )'; Quote Link to comment Share on other sites More sharing options...
jscix Posted February 11, 2007 Author Share Posted February 11, 2007 I actually tried a few things... which did not work... $query = 'CREATE TABLE ` .$dbusr. ` ( `. $dbpw. ` varchar(26) NOT NULL, PRIMARY KEY (` .$dbusr. `) )'; and.. $query = 'CREATE TABLE ` . ($dbusr) . ` ( ` . ($dbpw) . ` varchar(26) NOT NULL, PRIMARY KEY (` . ($dbusr) . `) )'; what am I doing wrong now? .. ;o Quote Link to comment Share on other sites More sharing options...
papaface Posted February 11, 2007 Share Posted February 11, 2007 try $query = "CREATE TABLE $dbusr ($dbpw varchar(26) NOT NULL, PRIMARY KEY ($dbusr))"; Quote Link to comment Share on other sites More sharing options...
jscix Posted February 11, 2007 Author Share Posted February 11, 2007 It worked!, Tyvm! Quote Link to comment Share on other sites More sharing options...
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